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garri49 [273]
2 years ago
13

What is the diameter of a 2m circle?

Mathematics
2 answers:
Nezavi [6.7K]2 years ago
7 0
Answer
2*2=4

Explanation
The diameter of a circle is the distance from one edge to the other, passing through the center. It is twice the radius.

So the diameter would be 2 cause 2 x 2=4
Varvara68 [4.7K]2 years ago
6 0

Answer:

If 2m is the radius, the diameter is 4 meters.

2*2=4

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Which shape is both rectangle and a square?
mina [271]

Step-by-step explanation:

the rhombus is both rectangle and square

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2 years ago
Read 2 more answers
Consider the linear transformation T from V = P2 to W = P2 given by T(a0 + a1t + a2t2) = (2a0 + 3a1 + 3a2) + (6a0 + 4a1 + 4a2)t
Svet_ta [14]

Answer:

[T]EE=\left[\begin{array}{ccc}2&3&3\\6&4&4\\-2&3&4\end{array}\right]

Step-by-step explanation:

First we start by finding the dimension of the matrix [T]EE

The dimension is : Dim (W) x Dim (V) = 3 x 3

Because the dimension of P2 is the number of vectors in any basis of P2 and that number is 3

Then, we are looking for a 3 x 3 matrix.

To find [T]EE we must transform the vectors of the basis E and then that result express it in terms of basis E using coordinates and putting them into columns. The order in which we transform the vectors of basis E is very important.

The first vector of basis E is e1(t) = 1

We calculate T[e1(t)] = T(1)

In the equation : 1 = a0

T(1)=(2.1+3.0+3.0)+(6.1+4.0+4.0)t+(-2.1+3.0+4.0)t^{2}=2+6t-2t^{2}

[T(e1)]E=\left[\begin{array}{c}2&6&-2\\\end{array}\right]

And that is the first column of [T]EE

The second vector of basis E is e2(t) = t

We calculate T[e2(t)] = T(t)

in the equation : 1 = a1

T(t)=(2.0+3.1+3.0)+(6.0+4.1+4.0)t+(-2.0+3.1+4.0)t^{2}=3+4t+3t^{2}

[T(e2)]E=\left[\begin{array}{c}3&4&3\\\end{array}\right]

Finally, the third vector of basis E is e3(t)=t^{2}

T[e3(t)]=T(t^{2})

in the equation : a2 = 1

T(t^{2})=(2.0+3.0+3.1)+(6.0+4.0+4.1)t+(-2.0+3.0+4.1)t^{2}=3+4t+4t^{2}

Then

[T(t^{2})]E=\left[\begin{array}{c}3&4&4\\\end{array}\right]

And that is the third column of [T]EE

Let's write our matrix

[T]EE=\left[\begin{array}{ccc}2&3&3\\6&4&4\\-2&3&4\end{array}\right]

T(X) = AX

Where T(X) is to apply the transformation T to a vector of P2,A is the matrix [T]EE and X is the vector of coordinates in basis E of a vector from P2

For example, if X is the vector of coordinates from e1(t) = 1

X=\left[\begin{array}{c}1&0&0\\\end{array}\right]

AX=\left[\begin{array}{ccc}2&3&3\\6&4&4\\-2&3&4\end{array}\right]\left[\begin{array}{c}1&0&0\\\end{array}\right]=\left[\begin{array}{c}2&6&-2\\\end{array}\right]

Applying the coordinates 2,6 and -2 to the basis E we obtain

2+6t-2t^{2}

That was the original result of T[e1(t)]

8 0
3 years ago
Quadrilateral A'B'C'D' is the image of quadrilateral ABCD under a dilation
Talja [164]
Correct answer is B.
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3 years ago
(3,5),slope -2<br><br> Show work
vova2212 [387]

Answer:

y=-2x+11

Step-by-step explanation:

equation of a line

y-b=m(x-a)

m=-2

a=3

b=5

sub into the equation

y-5= -2(x-3) multiply out the brackets and a negative multiply by negative equals positive

y-5=-2x+6

y=-2x+11

or

2x+y-11=0

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2 years ago
What is the probability of flipping a coin 50 times and getting tails 24 times or
Allisa [31]

Answer: 44.4%

Step-by-step explanation:

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