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dezoksy [38]
3 years ago
6

18,000 amounts to 21,600 in 4 years at simple interest. Find the sum of

Mathematics
1 answer:
AnnyKZ [126]3 years ago
3 0

Answer:

\$20,400

Step-by-step explanation:

we know that

The simple interest formula is equal to

A=P(1+rt)

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest  

t is Number of Time Periods

step 1

Find the rate of interest

in this problem we have

t=4\ years\\ P=\$18,000\\ A=\$21,600\\r=?

substitute in the formula above and solve for r

\$21,600=\$18,000(1+4r)

1.2=(1+4r)

4r=1.2-1

r=0.2/4=0.05

The rate of interest is 5\%

step 2

Find the sum of  money that will amount to 25,500 in 5 years, at the same rate of interest

in this part we have

t=5\ years\\ P=?\\ A=\$25,500\\r=0.05

substitute in the formula above and solve for P

\$25,500=P(1+0.05*5)

P=\$25,500/(1.25)=\$20,400

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Step-by-step explanation:

Define the following:

x = cost of fabric per yard

Make an equation:

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From a large number of actuarial exam scores, a random sample of scores is selected, and it is found that of these are passing s
Mnenie [13.5K]

<u>Supposing 60 out of 100 scores are passing scores</u>, the 95% confidence interval for the proportion of all scores that are passing is (0.5, 0.7).

  • The lower limit is 0.5.
  • The upper limit is 0.7.

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of \alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of \frac{1+\alpha}{2}.

60 out of 100 scores are passing scores, hence n = 100, \pi = \frac{60}{100} = 0.6

95% confidence level

So \alpha = 0.95, z is the value of Z that has a p-value of \frac{1+0.95}{2} = 0.975, so z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6 - 1.96\sqrt{\frac{0.6(0.4)}{100}} = 0.5

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6 + 1.96\sqrt{\frac{0.6(0.4)}{100}} = 0.7

The 95% confidence interval for the proportion of all scores that are passing is (0.5, 0.7).

  • The lower limit is 0.5.
  • The upper limit is 0.7.

A similar problem is given at brainly.com/question/16807970

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3 years ago
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