Answer:
Horizontal asymptote of the graph of the function f(x) = 25/1+4x is y=0
Step-by-step explanation:
I attached the graph of the function. Graphically it can be seen that the horizontal asymptote of the graph of the function is y=0. There is also a <em>vertical</em> asymptote at x=-1/4
When denominator's degree (1) is higher than nominator's degree (0) then the horizontal asymptote is y=0
Answer:
Discrete
Step-by-step explanation:
The points that you would plot are (1,3) (2,11), etc. You would not be able to draw a line because you can't have like 1/2 of a customer.
Circumference: C=2pir
C stands for circumference. pi is 3.14... and r is the radius.
of course, you can always do, C=pid. where d is diameter because the radius is half the diameter
Area: A=pir^2
A stands for the Area, pi stands for 3.14... r stands for radius, and the little ^2 is the equation squared. The way to solve that is square the radius and then multiply what you got from squaring the radius by pi.
DO NOT replace radius with the diameter when trying to find the Area
Try this option:
A. f(4)=7 - false; explanation: x=4, it means that x>0 and x²-1=4²-1=15 ⇒ f(4)=15.
B. f(1)=0 - true; explanation: x=1, it means that x>0 and x²-1=1-1=0.
C. f(-1)=2 - true; explanation: x=-1, it means that x<0 and -x+1=1+1=2.
D. f(-2)=0 - false; explanation: x=-2, it means that x<0 and -x+1=2+1=3 ⇒ f(-2)=3.
209.95 to find the area/volume of a triangle you do base times hight divided by 2
