All categories

2 years ago

Find the area of the trapezoid

Mathematics

1 answer:

Sergeeva-Olga [200]2 years ago

6 0

Answer:

Step-by-step explanation:

Formula

$\frac{1}{2} \times h \times (sum \: of \: parallel \: sides(b1 + b2))$

Your scale is 2cm to 2units therefore the parameters are as follows

h=4

b1=9

b2=13

$\frac{1}{2} \times 4 \times (9 + 13)$

$\frac{1}{2} \times 4 \times 22$

$\frac{1}{2} \times 88$

$\frac{88}{2} \\ = 44$

You might be interested in

Soit trois nombres consécutifs. Lorsque l’on soustrait le double du deuxième nombre du quadruple du

irina [24]

Answer:

Les trois nombres sont 5, 6 et 7.

Step-by-step explanation:

Soit x le premier nombre.

x + 1 sera le second et x + 2 sera le troisième.

On pose l'équation :

2x + 3(x + 1) = 4(x + 2)

2x + 3x + 3 = 4x + 8

5x - 4x = 8 - 3

x = 5

4 0

2 years ago

684303 rounded to nearest thousand

horsena [70]

684,000. This should give you the correct answer as the 4 is the thousands place. Good luck :D

3 0

2 years ago

My last question plz help me

LenKa [72]

The answer is c I hope this helps

4 0

2 years ago

Read 2 more answers

Which is the inverse of the function a(d)=5d-3? And use the definition of inverse functions to prove a(d) and a-1(d) are inverse

Drupady [299]

Answer:

$a'(d) = \frac{d}{5} + \frac{3}{5}$

$a(a'(d)) = a'(a(d)) = d$

Step-by-step explanation:

Given

$a(d) = 5d - 3$

Solving (a): Write as inverse function

$a(d) = 5d - 3$

Represent a(d) as y

$y = 5d - 3$

Swap positions of d and y

$d = 5y - 3$

Make y the subject

$5y = d + 3$

$y = \frac{d}{5} + \frac{3}{5}$

Replace y with a'(d)

$a'(d) = \frac{d}{5} + \frac{3}{5}$

Prove that a(d) and a'(d) are inverse functions

$a'(d) = \frac{d}{5} + \frac{3}{5}$ and $a(d) = 5d - 3$

To do this, we prove that:

$a(a'(d)) = a'(a(d)) = d$

Solving for $a(a'(d))$

$a(a'(d)) = a(\frac{d}{5} + \frac{3}{5})$

Substitute $\frac{d}{5} + \frac{3}{5}$ for d in $a(d) = 5d - 3$

$a(a'(d)) = 5(\frac{d}{5} + \frac{3}{5}) - 3$

$a(a'(d)) = \frac{5d}{5} + \frac{15}{5} - 3$

$a(a'(d)) = d + 3 - 3$

$a(a'(d)) = d$

Solving for: $a'(a(d))$

$a'(a(d)) = a'(5d - 3)$

Substitute 5d - 3 for d in $a'(d) = \frac{d}{5} + \frac{3}{5}$

$a'(a(d)) = \frac{5d - 3}{5} + \frac{3}{5}$

Add fractions

$a'(a(d)) = \frac{5d - 3+3}{5}$

$a'(a(d)) = \frac{5d}{5}$

$a'(a(d)) = d$

Hence:

$a(a'(d)) = a'(a(d)) = d$

7 0

2 years ago

the height of a plant in centimeters is modeled as a function of time, in days. consider this graph of the function enter the av

MrRa [10]

The average rate of change for the height of the plant measured in centimeters per day between day 0 and day 20 is 1.32 cm per day.

<h3>What is average height?</h3>

The average height is the ratio of change in height of the plant and the time taken taken for that change.

Given is the height of a plant in centimeters is modeled as a function of time, in days.

For day 0, the height is 18cm and the height for day 20 is 42 cm, then the average height change is

height per day = 42 - 18/ 20 -0

height per day = 1.2 cm/day

Thus, the average height of plant is 1.2 cm/day.

Learn more about average height.

brainly.com/question/16490045

#SPJ1

6 0

1 year ago