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GarryVolchara [31]
3 years ago
9

Elton is a candle maker. Each 15 long candle he makes burns evenly for 666 hours.

Mathematics
1 answer:
lyudmila [28]3 years ago
4 0

Answer:

1998

Step-by-step explanation:

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If the function rule is 5x, what is the value when x = 3?
cupoosta [38]
This means that we will plug 3 into our x values.

Our rule is 5x.

This means that:
5(3)

This means our final answer will be 15.
3 0
2 years ago
A company that produces fine crystal knows from experience that 13% of its goblets have cosmetic flaws and must be classified as
Kisachek [45]

Answer:

(a) The probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b) The probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c) The probability that at most five must be selected to find four that are not seconds is 0.9453.

Step-by-step explanation:

Let <em>X</em> = number of seconds in the batch.

The probability of the random variable <em>X</em> is, <em>p</em> = 0.31.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The probability mass function of <em>X</em> is:

P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,3...

(a)

Compute the probability that only one goblet is a second among six randomly selected goblets as follows:

P(X=1)={6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=6\times 0.13\times 0.4984\\=0.3888

Thus, the probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b)

Compute the probability that at least two goblet is a second among six randomly selected goblets as follows:

P (X ≥ 2) = 1 - P (X < 2)

              =1-{6\choose 0}0.13^{0}(1-0.13)^{6-0}-{6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=1-0.4336+0.3888\\=0.1776

Thus, the probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c)

If goblets are examined one by one then to find four that are not seconds we need to select either 4 goblets that are not seconds or 5 goblets including only 1 second.

P (4 not seconds) = P (X = 0; n = 4) + P (X = 1; n = 5)

                            ={4\choose 0}0.13^{0}(1-0.13)^{4-0}+{5\choose 1}0.13^{1}(1-0.13)^{5-1}\\=0.5729+0.3724\\=0.9453

Thus, the probability that at most five must be selected to find four that are not seconds is 0.9453.

8 0
3 years ago
You make $443 per week, and have claimed five exemptions. How much money will be withheld from you in a year? For weekly gross i
disa [49]

Answer:

Choice A. $2,392 is the correct answer :)

Step-by-step explanation:

3 0
3 years ago
Two cars leave Denver at the same time and travel in opposite directions. One car travels 10 mi/h faster than the other car. The
LuckyWell [14K]

Answer:

D.) 50 mi/h and 60 mi/h

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
One side of a kite is 5 cm less than 2 times the length of another. If the perimeter is 14 cm, find the length of each side of t
Phoenix [80]
<h3>Answer:</h3>

D) 4 cm, 3 cm

<h3>Step-by-step explanation:</h3>

Let x represent the length of "another" side. Then "one side" can be represented by (2x -5 cm).

The perimeter of the kite is the sum of two sides of each length:

... P = 14 cm = 2(x) + 2(2x -5 cm)

Dividing by 2 and collecting terms, we have ...

... 7 cm = 3x -5 cm

... 12 cm = 3x

... 4 cm = x . . . . the length of "another" side

... 2(4 cm) -5 cm = 3 cm . . . . the length of "one side"

The two different side lengths are 4 cm and 3 cm.

7 0
3 years ago
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