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Nesterboy [21]
3 years ago
7

F ∝ a If F = 48 when a = 3 find, a when F = 32

Mathematics
1 answer:
LenKa [72]3 years ago
4 0

Answer:

2

Step-by-step explanation:

f = a

48 = 3

32 = x

48x= 98

<u>x=2</u>

<h2><u>Mark me as brainiest if i helped you </u></h2>
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An elementary school is offering 2 language classes: one in Spanish (S) and one in French (F). Given that P(S) = 50%, P(F) = 40%
nikklg [1K]

Answer:

(a) Probability that a randomly selected student is taking Spanish given that he or she is taking French = 0.5 .

(b) Probability that a randomly selected student is not taking French given that he or she is not taking Spanish = 0.6 .

Step-by-step explanation:

We are given that an elementary school is offering 2 language classes ;

 <em>Spanish Language is denoted by S and French language is denoted by F.</em>

Also we are given, P(S) = 0.5 {Probability of students taking Spanish language}

P(F) = 0.4 {Probability of students taking French language}

P(S\bigcup F) = 0.7 {Probability of students taking Spanish or French Language}

<em>We know that,  </em>P(A\bigcup B)<em>  = </em>P(A) + P(B) -<em> </em>P(A\bigcap B)<em />

So, P(S\bigcap F) = P(S) + P(F) - P(S\bigcup F) = 0.5 + 0.4 - 0.7 = 0.2

P(S\bigcap F) means Probability of students taking  both Spanish and French Language.

Also, P(S)' = 1 - P(S) = 1 - 0.5 = 0.5

         P(F)' = 1 - P(F) = 1 - 0.4 = 0.6

        P(S'\bigcap F') = 1 -  P(S\bigcup F) = 1 - 0.7 = 0.3

(a) Probability that a randomly selected student is taking Spanish given that he or she is taking French is given by P(S/F);

  P(S/F) = \frac{P(S\bigcap F)}{P(F)} = \frac{0.2}{0.4} = 0.5

(b) Probability that a randomly selected student is not taking French given that he or she is not taking Spanish is given by P(F'/S');

   P(F'/S') = \frac{P(S'\bigcap F')}{P(S')} = \frac{1- P(S\bigcup F)}{1-P(S)} = \frac{0.3}{0.5} = 0.6 .

Note: 2. A pair of fair dice is rolled until a sum of either 5 or 7 appears  ; This question is incomplete please provide with complete detail.

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