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IRISSAK [1]
2 years ago
15

There is an outbuilding that has an area of 80 square feet. The rectangle on the blueprint that represents the outbuilding has a

n area of 20 square inches. If the actual outbuilding has a wall length of 10 feet, what is the length of that wall on the blueprint . A) 3 B) 4 C) 5 D) 6
Mathematics
1 answer:
Tanya [424]2 years ago
8 0

Answer:

B) 4

Step-by-step explanation:

There is an outbuilding that has an area of 80 square feet. The rectangle on the blueprint that represents the outbuilding has an area of 20 square inches. If the actual outbuilding has a wall length of 10 feet, what is the length of that wall on the blueprint . A) 3 B) 4 C) 5 D) 6

The length of the wall on the blue print can be calculated as:

20 square feet ÷ 5

= 4 feet

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Answer: R=20.84\ lb\quad 22.57^{\circ},15.43^{\circ}

Step-by-step explanation:

Given

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\Rightarrow \alpha=\tan^{-1}\left( \dfrac{b\sin \theta}{a+b\cos \theta}\right)\\\\\text{Considering 9 lb force along the x-axis}\\\\\Rightarrow \alpha =\tan^{-1}\left( \dfrac{13\sin 38^{\circ}}{9+13\cos 38^{\circ}}\right)\\\\\Rightarrow \alpha =\tan^{-1}(\dfrac{8}{19.244})\\\\\Rightarrow \alpha=22.57^{\circ}

So, the resultant makes an angle of 22.57^{\circ} with 9 lb force

Angle made with 13 lb force is 38^{\circ}-22.57^{\circ}=15.43^{\circ}

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