Answer:
b+6
Problem:
If the average of b and c is 8, and d=3b-4, what is the average of c and d in terms of b?
Step-by-step explanation:
We are given (b+c)/2=8 and d=3b-4.
We are asked to find (c+d)/2 in terms of variable, b.
We need to first solve (b+c)/2=8 for c.
Multiply both sides by 2: b+c=16.
Subtract b on both sides: c=16-b
Now let's plug in c=16-b and d=3b-4 into (c+d)/2:
([16-b]+[3b-4])/2
Combine like terms:
(12+2b)/2
Divide top and bottom by 2:
(6+1b)/1
Multiplicative identity property applied:
(6+b)/1
Anything divided by 1 is that anything:
(6+b)
6+b
b+6
Answer:
9.2
Step-by-step explanation:
Answer:
B is the closet to pi hsiebfjwjgsbe9fbe
Answer:
Option D, 16/21
Step-by-step explanation:
<u>Step 1: Add all of them together</u>
5 + 7 + 9
21
<u>Step 2: Figure out how much of the plants are medicinal</u>
7 + 9
16
<u>Step 3: Figure out the probability </u>
16/21
Answer: Option D, 16/21
Answer:
-4.6
because you add whats inside teh parenthesis then subtract by 12 before dividing by 23