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Amiraneli [1.4K]
3 years ago
12

Factor completely 25xsquared-16

Mathematics
2 answers:
cestrela7 [59]3 years ago
8 0

Step-by-step explanation:

25x² - 16

= (5x)² - (4)²

= (5x + 4)(5x - 4).

chubhunter [2.5K]3 years ago
7 0

Answer:

(5x - 4)(5x + 4)

Step-by-step explanation:

25 {x}^{2}  - 16 \\  \\  =  {(5x)}^{2}  -  {(4)}^{2}  \\  \\  = (5x - 4)(5x + 4)

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zaharov [31]

Answer:

1. a. 25(1) + 10(2) + 3(3) + 10(4) = 94/140 = .671

2. b. Mark’s average < Jay’s average

Step-by-step explanation:

1. What is Mark’s slugging average?

The slugging average gives more weight to the multi-base hits (compared to single-base hits) in opposition with the batting average.

So, a single hit is worth 1 point, a double is worth 2 points, a triple 3 points and a homerun is worth 4 points.  It's a weighted average calculation.

Mark had 25 singles, 10 doubles, 3 triples and 10 homeruns during 140 presences 140 at bat.

25(1) + 10(2) + 3(3) + 10(4) = 94/140 = .671

2. How does Mark's average compares to Jay's?

Let's first calculate Jay's slugging average then we'll be able to decide.

Jay had 10 singles, 6 doubles, 5 triples and 14 homeruns in 90 presences.

10 (1) + 6 (2) + 5 (3) + 14 (4) = 10+12+15+56 = 93 / 90 = 1.033

We can definitely say that Mark's slugging average (0.671) calculated above is lower than Jay's average (1.033).  So,

b. Mark’s average < Jay’s average

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An experiment is completed where a coin is flipped and a six-sided die (singular for dice) is rolled. The outcomes from the expe
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Answer:

1) 16\frac{2}{3}% or 20%

Step-by-step explanation:

Given that:

An experiment which is carried out by flipping a coin and rolling six sided die.

The outcomes can be:

{H1, H2, H3, H5, H6, T1, T1, T2, T3, T5}

As per question statement:

Number of outcomes having tails and an odd number greater than one is 2 (i.e. T3 and T5)

Total number of outcomes here is 10.

Therefore, to find the percentage, we use the following formula:

\dfrac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}\times 100

\Rightarrow \dfrac{2}{10}\times 100 = 20\%

As per question statement, the answer is 20%.

If we consider all the outcomes, i.e.

{H1, H2, H3, H4, H5, H6, T1, T2, T3, T4, T5, T6}

Total number of outcomes = 12

The percentage will come out be :

\Rightarrow \dfrac{2}{12}\times 100 = 16\frac{2}{3}\%

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