Answer:
They will expect the ratio below:
x/20 = 160/8, with x: population
Then
x = 20x160/8 = 400
Answer: The least common multiple of 4 and 6 is 12 because this is the smallest positive integer that is divisible by both 4 and 6.
Step-by-step explanation:
- The least common multiple of two integers m and n is the least positive integer that is divisible by both m and n.
We are given that :
The first five multiples for the numbers 4 and 6 are shown below.
![\text{ Multiples of 4: 4, 8, 12, 16, 20, . . . }\\\\\text{Multiples of 6: 6, 12, 18, 24, 30, . . . }](https://tex.z-dn.net/?f=%5Ctext%7B%20Multiples%20of%204%3A%204%2C%208%2C%2012%2C%2016%2C%2020%2C%20.%20.%20.%20%7D%5C%5C%5C%5C%5Ctext%7BMultiples%20of%206%3A%206%2C%2012%2C%2018%2C%2024%2C%2030%2C%20.%20.%20.%20%7D)
We can see that from the multiples of 4 and 6 , the least common multiple of 4 and 6 =12 such that 12 is divisible by 4 and 6 .
There are many polygons that have four sides... for example:
- Square
- Rectangle
- Rhombus
- Parallelogram
- Kite
- Trapezoid
And also irregular ones as well but the ones above have proper terms/names
I hope this helps! ^__^
<em>10 meters.</em>
Step-by-step explanation:
To find the missing side of a right triangle, we can use the <u>Pythagorean theorem</u>.
The Pythagorean theorem is...
![a^2+b^2=c^2](https://tex.z-dn.net/?f=a%5E2%2Bb%5E2%3Dc%5E2)
Please be sure to note that a and b will <em>always </em>be the length of the sides and c will <em>always </em>be the hypotenuse, or in this case the ramp.
Since we know the values of both of the sides we can plug this into the theorem.
![6^2+8^2=c^2](https://tex.z-dn.net/?f=6%5E2%2B8%5E2%3Dc%5E2)
Now we can solve.
![36+64+c^2](https://tex.z-dn.net/?f=36%2B64%2Bc%5E2)
Add.
![100=c^2](https://tex.z-dn.net/?f=100%3Dc%5E2)
Many people will make the mistake of thinking 100 is the final answer, but since c is squared we need to find the square root of 100.
![\sqrt{100} =10](https://tex.z-dn.net/?f=%5Csqrt%7B100%7D%20%3D10)
c = 10
<em><u>The ramp is 10 meters.</u></em>
• Increased by 3
n+3
• Twice the number
2(n+3)
• Three times the number
3n
• Final result
2(n+3)-3n