Answer:
Let b=x
Such that b^2 =8b-8 will x^2=8x-8
Using the almighty quadratic formula
x1={-b+sqrt (b^2-4ac)}/2a
x2={-b-sqrt (b^2-4ac)}/2a
From the question
a=1
b=8
c=-8
x1={-8+sqrt (8^2-4(-8))}/2
x1=(-8+5.66)/2
x1=-1.17
x2={-8-sqrt (8^2-4(-8))}/2
x2=(-8-5.66)/2
x2=-6.83
:.(x1,x2)=(-1.17,-6.83)
Step-by-step explanation:
