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Ray Of Light [21]
3 years ago
14

Solve each equation with the quadratic formula. (Show work please)

Mathematics
1 answer:
Snowcat [4.5K]3 years ago
3 0

Answer:

Let b=x

Such that b^2 =8b-8 will x^2=8x-8

Using the almighty quadratic formula

x1={-b+sqrt (b^2-4ac)}/2a

x2={-b-sqrt (b^2-4ac)}/2a

From the question

a=1

b=8

c=-8

x1={-8+sqrt (8^2-4(-8))}/2

x1=(-8+5.66)/2

x1=-1.17

x2={-8-sqrt (8^2-4(-8))}/2

x2=(-8-5.66)/2

x2=-6.83

:.(x1,x2)=(-1.17,-6.83)

Step-by-step explanation:

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Step-by-step explanation:

4 0
3 years ago
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How do you solve for 5/6w = 2/3 (the answer is w= 4/5) I just don’t know how to show it.
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Answer:

5/6w=2/3

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Proof:

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In the diagram, the circle will be dilated by a scale factor of 3 about the origin. The points C, A, and B map to C', A', and B'
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Original coordinates of the points:
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The given image forms a right triangle. So, I'll get the short leg and long leg of the right triangle to solve for the hypotenuse, length of CB.

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Long leg: x value of B and C
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a² + b² = c²
9² + 12² = c²
81 + 144 = c²
225 = c²
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If a determinant of a 2 x 2 matrix is 0, what can you conclude about the inverse of the matrix?
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Any singular matrix (a matrix with zero determinant) has no inverse.
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2 years ago
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3 years ago
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