I am pretty sure number 3 is the right answer
Answer:
The clock face is divided into sixty equal parts, each minute. The minute hand is located on the 20 minute mark at 6:20, the hour hand located between the 30 minute mark and the 35 minute mark. When the minute hand goes all sixty minutes, the hour hand only moves five, so to figure out the location of the hour hand, we look at how much the hour has progressed, in this case 20 minutes, or one third of the hour. So the minute hand has moved one third of the way through the hour, so has the hour hand moved one third of the way through the five minutes, or, five thirds of a minute, which is one and two thirds minute, one minute forty seconds. That puts the hour hand at thirty minutes plus one minute and forty seconds—at 31min 40sec—which is 11min 40sec farther than the minute hand.
Step-by-step explanation:
Answer:
a = 7, b = ![\frac{7\sqrt{3} }{3}](https://tex.z-dn.net/?f=%5Cfrac%7B7%5Csqrt%7B3%7D%20%7D%7B3%7D)
Step-by-step explanation:
Using the sine ratio in the left right triangle and the exact value
sin45° =
, then
sin45° =
=
=
( cross- multiply )
a ×
= 7
( divide both sides by
)
a = 7
--------------------------------------------------------
Using the tangent ratio in the right triangle on the right and the exact value
tan60° =
, then
tan60° =
=
=
=
( multiply both sides by b )
b ×
= 7 ( divide both sides by
)
b =
×
= ![\frac{7\sqrt{3} }{3}](https://tex.z-dn.net/?f=%5Cfrac%7B7%5Csqrt%7B3%7D%20%7D%7B3%7D)
Answer:
36 feet.
Step-by-step explanation:
We have been given that a ball is thrown upward from ground level. Its height h, in feet, above the ground after t seconds is
. We are asked to find the maximum height of the ball.
We can see that our given equation is a downward opening parabola, so its maximum height will be the vertex of the parabola.
To find the maximum height of the ball, we need to find y-coordinate of vertex of parabola.
Let us find x-coordinate of parabola using formula
.
![x=-\frac{-48}{2(-16)}](https://tex.z-dn.net/?f=x%3D-%5Cfrac%7B-48%7D%7B2%28-16%29%7D)
![x=-\frac{48}{32}](https://tex.z-dn.net/?f=x%3D-%5Cfrac%7B48%7D%7B32%7D)
![x=-\frac{3}{2}](https://tex.z-dn.net/?f=x%3D-%5Cfrac%7B3%7D%7B2%7D)
So, the x-coordinate of the parabola is
. Now, we will substitute
in our given equation to find y-coordinate of parabola.
![h(t)=-48t -16t^2](https://tex.z-dn.net/?f=h%28t%29%3D-48t%20-16t%5E2)
![h(-\frac{3}{2})=-48(-\frac{3}{2})-16(-\frac{3}{2})^2](https://tex.z-dn.net/?f=h%28-%5Cfrac%7B3%7D%7B2%7D%29%3D-48%28-%5Cfrac%7B3%7D%7B2%7D%29-16%28-%5Cfrac%7B3%7D%7B2%7D%29%5E2)
![h(-\frac{3}{2})=-24(-3)-16(\frac{9}{4})](https://tex.z-dn.net/?f=h%28-%5Cfrac%7B3%7D%7B2%7D%29%3D-24%28-3%29-16%28%5Cfrac%7B9%7D%7B4%7D%29)
![h(-\frac{3}{2})=72-4*9](https://tex.z-dn.net/?f=h%28-%5Cfrac%7B3%7D%7B2%7D%29%3D72-4%2A9)
![h(-\frac{3}{2})=72-36](https://tex.z-dn.net/?f=h%28-%5Cfrac%7B3%7D%7B2%7D%29%3D72-36)
![h(-\frac{3}{2})=36](https://tex.z-dn.net/?f=h%28-%5Cfrac%7B3%7D%7B2%7D%29%3D36)
Therefore, the maximum height of the ball is 36 feet.