To check the decay rate, we need to check the variation in y-axis.
Since our interval is
![-2We need to evaluate both function at those limits.At x = -2, we have a value of 4 for both of them, at x = 0 we have 1 for the exponential function and 0 to the quadratic function. Let's call the exponential f(x), and the quadratic g(x).[tex]\begin{gathered} f(-2)=g(-2)=4 \\ f(0)=1 \\ g(0)=0 \end{gathered}](https://tex.z-dn.net/?f=-2We%20need%20to%20evaluate%20both%20function%20at%20those%20limits.%3Cp%3E%3C%2Fp%3E%3Cp%3EAt%20x%20%3D%20-2%2C%20we%20have%20a%20value%20of%204%20for%20both%20of%20them%2C%20at%20x%20%3D%200%20we%20have%201%20for%20the%20exponential%20function%20and%200%20to%20the%20quadratic%20function.%20Let%27s%20call%20the%20exponential%20f%28x%29%2C%20and%20the%20quadratic%20g%28x%29.%3C%2Fp%3E%3Cp%3E%3C%2Fp%3E%5Btex%5D%5Cbegin%7Bgathered%7D%20f%28-2%29%3Dg%28-2%29%3D4%20%5C%5C%20f%280%29%3D1%20%5C%5C%20g%280%29%3D0%20%5Cend%7Bgathered%7D)
To compare the decay rates we need to check the variation on the y-axis of both functions.
Now, we calculate their ratio to find how they compare:
This tell us that the exponential function decays at three-fourths the rate of the quadratic function.
And this is the fourth option.
Answer:
174 ft²
Step-by-step explanation:
Assuming you're interested in the area of the figure, you can compute it as the sum of the areas of the triangle and rectangle.
The unknown side of the triangle can be figured from the overall dimension of the rectangle and the two lengths that are not part of the triangle base:
6 ft + triangle base + 6 ft = 18 ft
triangle base = 18 ft - 12 ft = 6 ft
Then the area of the triangle is ...
A = 1/2bh = 1/2(6 ft)(4 ft) = 12 ft²
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Of course, the area of the rectangle is the product of its length and width:
A = LW = (18 ft)(9 ft) = 162 ft²
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The total area of the figure is the sum of these:
area = triangle area + rectangle area
area = 12 ft² +162 ft²
area = 174 ft²
THE ANSWER WOULD BE X=2/3
Answer:
C) -9.6
Step-by-step explanation:
