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3 years ago

A jacket is advertised to be 80% of the original price. It the original price is $350, what is the sale price?

Mathematics

2 answers:

Afina-wow [57]3 years ago

3 0

Answer:

70$

Step-by-step explanation:

350 - 80%

Lera25 [3.4K]3 years ago

3 0

Answer:

Step-by-step explanation:

350*80=28000

28000/100=280

350-280=70

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Rewrite the expression using GCF and distributive property. 64x-24

Ede4ka [16]

The greatest common factor between 64 and 24 is 8

Let's divide both terms in the expression by 8 and leave the expression in parenthesis...

Like this!

64x -24

$\frac{64x}{8} - \frac{24}{8}$

8x - 3

Leave 8 we divided outside the parenthesis

Now we have this!

8( 8x - 3)

This is the distributive property form!

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Out of the 40 students in the 7th grade 60% of the students carry cell phones. What fraction of the students carry a cell phone?

nexus9112 [7]

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What is the value of z in the equation 2z + 8 = −6? −1 −7 1 7

vitfil [10]

Answer:

So the answer is -7

Step-by-step explanation:

2z + 8 = −6

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4 0

3 years ago

The random variable X has the following probability density function: fX(x) = ( xe−x , if x > 0 0, otherwise. (a) Find the mo

dusya [7]

Answer:

Follows are the solution to the given points:

Step-by-step explanation:

Given value:

$\to f_X (x) \ \ xe^{-x} \ , \ x>0$

For point a:

Moment generating function of X=?

Using formula:

$\to M(t) =E(e^{tx})= \int^{\infty}_{-\infty} \ e^{tx} f(x) \ dx$

$M(t) = \int^{\infty}_{-\infty} \ e^{tx}xe^{-x} \ dx = \int^{\infty}_{0} \ xe^{(t-1)x} \ dx$

integrating the values by parts:

$u = x \\\\dv = e^{(t-1)x}\\\\dx =dx \\\\v= \frac{e^{(t-1)x}}{t-1}\\\\M(t) =[\frac{e^{(t-1)x}}{t-1}]^{-\infty}_{0} -\int^{\infty}_{0} \frac{e^{(t-1)x}}{t-1} \ dx\\\\$

$= \frac{1}{t-1} (0) - [\frac{e^{(t-1)x}}{(t-1)^2}]^{\infty}_{0}\\\\=\frac{1}{(t-1)^2}(0-1)\\\\=\frac{1}{(t-1)^2}\\\\$

Therefore, the moment value generating by the function is $=\frac{1}{(t-1)^2}$

In point b:

$E(X^n)=?$

Using formula: $E(X^n)= M^{n}_{X}(0)$

form point (a):

$\to M_{X}(t)=\frac{1}{(t-1)^2}$

Differentiating the value with respect of t

$M'_{X}(t)=\frac{-2}{(t-1)^3}$

when $t=0$

$M'_{X}(0)=\frac{-2}{(0-1)^3}= \frac{-2}{(-1)^3}= \frac{-2}{-1}=2\\\\M''_{X}(t)=\frac{(-2)(-3)}{(t-1)^4}\\\\M''_{X}(0)=\frac{(-2)(-3)}{(0-1)^4}= \frac{6}{(-1)^4}= \frac{6}{1}=6\\\\M''_{X}(t)=\frac{(-2)(-3)}{(t-1)^4}\\\\M''_{X}(0)=\frac{(-2)(-3)}{(0-1)^4}= \frac{6}{(-1)^4}= \frac{6}{1}=6\\\\M'''_{X}(t)=\frac{(-2)(-3)(-4)}{(t-1)^5}\\\\M''_{X}(0)=\frac{(-2)(-3)(-4)}{(0-1)^5}= \frac{24}{(-1)^5}= \frac{24}{-1}=-24\\\\\therefore \\\\M^{K}_{X} (t)=\frac{(-2)(-3)(-4).....(k+1)}{(t-1)^{k+2}}\\\\$

$M^{K}_{X} (0)=\frac{(-2)(-3)(-4).....(k+1)}{(-1)^{k+2}}\\\\\therefore\\\\E(X^n) = \frac{(-2)(-3)(-4).....(n+1)}{(-1)^{n+2}}\\\\$

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2 years ago

Sally uses 5 1/5 of clay to make a set of four pots that are exactly the same.

ki77a [65]

Answer:

1 3/10

Step-by-step explanation:

5 1/5 ÷ 4= 1 3/10

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3 years ago