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Greeley [361]
3 years ago
9

What are two different names for this line

Mathematics
1 answer:
xxTIMURxx [149]3 years ago
8 0

Answer:

Hey mate.......

Step-by-step explanation:

This is ur answer.....

<h2>Horizontal line and Transverse line </h2>

Hope it helps!

Mark me brainliest plz.....

Follow me! ;)

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Is this "N2 + 3H2 → 2NH3" balanced or no?
romanna [79]
Yes, the equation “N2 + 3H2 = 2NH3” is balanced.
5 0
3 years ago
I need help with this question.
SSSSS [86.1K]

Answer:

\displaystyle S_{27}=675

Step-by-step explanation:

The sum of N consecutive natural numbers is given by:

\displaystyle S_N=\frac{N}{2}(F+L)

We need to find the sum of the natural numbers between 12 to 38.

To calculate the required sum we have F=12, L=38, but we don't have the value of N.

From 12 to 38 there are 38 - 12 + 1 = 27 natural consecutive numbers, thus N=27.

Substituting in the formula:

\displaystyle S_{27}=\frac{27}{2}(12+38)

\displaystyle S_{27}=\frac{27}{2}(50)

\displaystyle S_{27}=27*25

\mathbf{\displaystyle S_{27}=675}

5 0
3 years ago
Grandpa Simpson borrows $10,000 to buy a car. There is a 5 percent interest rate for each year. What is the total amount of inte
tester [92]
$10,000 X 0.05 = $500/year
500 X 4 years = $2,000 after 4 years
5 0
3 years ago
The weekly sales of Honolulu Red Oranges is given by q = 896 − 20p.(A) Calculate the price elasticity of demand when the price i
vitfil [10]

Answer with Step-by-step explanation:

Since we have given that

q = 896-20p

p = $32

.(A) Calculate the price elasticity of demand

As we know that

e=-\dfrac{dq}{dp}\times \dfrac{p}{q}\\\\e=-(-20)\times \dfrac{32}{896-20p}\\\\e=\dfrac{20\times 32}{896-20p}\\\\e=\dfrac{640}{896-20p}\\\\e=\dfrac{640}{896-640}\\\\e=\dfrac{640}{256}=2.5

(B) The demand is going down with increase in 15 increase in price at that price level, as we know that there is inverse relationship between price and quantity demanded.

(C)  Also, calculate the price that gives a maximum weekly revenue.

R=pq\\\\R=p(896-20p)\\\\R=896p-20p^2

We first find the first derivative:

R'(p)=896-400p

So, it becomes,

896-40p=0\\\\40p=896\\\\p=\dfrac{896}{40}=\$22.4

R=-40<0, so, it will give maximum revenue.

(D) Find this maximum revenue.

Maximum revenue would be R=pq\\\\R=22.4(896-20\times 22.4)\\\\R=\$10035.2

7 0
3 years ago
Solve the Quetion fine with the variable equals to make it true<br> (x+3)(x-5)=0 show your work
xenn [34]

Answer:

x=-3

Step-by-step explanation:

(-3+5) (-3-5)=0

(0) (-8)=0

0=0

7 0
3 years ago
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