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Greeley [361]
2 years ago
9

What are two different names for this line

Mathematics
1 answer:
xxTIMURxx [149]2 years ago
8 0

Answer:

Hey mate.......

Step-by-step explanation:

This is ur answer.....

<h2>Horizontal line and Transverse line </h2>

Hope it helps!

Mark me brainliest plz.....

Follow me! ;)

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The simple interest on a certain sum of money for 2 years at 5% per annum is Rs 320. What will be the compound interest on the s
Brilliant_brown [7]

Answer:

Rs 328

Step-by-step explanation:

Find the <u>principal</u> amount invested.

<u>Simple Interest Formula</u>

I = Prt

where:

  • I = interest earned
  • P = principal
  • r = interest rate (in decimal form)
  • t = time (in years)

Given:

  • I = Rs 320
  • r = 5% = 0.05
  • t = 2 years

Substitute the given values into the formula and solve for P:

⇒ 320 = P(0.05)(2)

⇒ 320 = P(0.1)

⇒ P = 3200

<u>Compound Interest Formula</u>

\large \text{$ \sf I=P\left(1+\frac{r}{n}\right)^{nt} -P$}

where:

  • I = interest earned
  • P = principal amount
  • r = interest rate (in decimal form)
  • n = number of times interest applied per time period
  • t = number of time periods elapsed

Given:

  • P = 3200
  • r = 5% = 0.05
  • n = 1 (annually)
  • t = 2 years

Substitute the given values into the formula and solve for I:

\implies \sf I=3200\left(1+\frac{0.05}{1}\right)^{2} -3200

\implies \sf I=3200\left(1.05\right)^{2} -3200

\implies \sf I=3200\left(1.1025\right) -3200

\implies \sf I=3528-3200

\implies \sf I=328

Therefore, the compound interest on the same sum for the same time at the same rate is Rs 328.

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2 years ago
To produce x units of a religious medal costs Upper C (x )equals 13 x plus 120. The revenue is Upper R (x )equals 33 x. Both cos
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Answer:

Step-by-step explanation:

the answer is  458                                          because  thats the right answer

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3 years ago
Help I need to find x and I need to show work plz help and thanks
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3 years ago
A bridge on a river is modeled by the equation h = -0.2d^2 + 2.25d, where h is the height and d is the horizontal distance. For
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Hello,
A=(2.21082279...,3.996803798)
\left \{ {{h=-0.2d^2+2.25d} \atop {h=d/6+21.77/6}} \right. \\\\&#10;&#10;\Rightarrow\ 1.2d^2-12.5d+21.77=0\\\\&#10;&#10;\Rightarrow\ d=2.21082279..\ or\ d=8.20584..\\\\&#10;&#10;


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