Part A.
The venn diagram is attached. In the venn diagram, circle A represent the number of responds that have an ASU parking deal. Circle B represent the number of respondents that ride their bike to campus and circle C represent the number of respondents that that ride the Light Rail.
Part B.
From the venn diagram, the number of respondents that ride the Light Rail and ride their bike to campus is given by 39 –
12 = 27
Part C.
From the venn diagram, the number of respondents that only have an ASU parking decal is given by <span>77 –
12 – 8 – 6 = 51
Part D.
The number of respondents that ride the Light Rail or have an ASU decal is given by the sum of the number of respondents that ride the Light Rail only and those that have an ASU parking decal and those that have both ASU parking decal and ride their bike to school.
This is given by 51 + 8 + 28 = 87.
Part E.
The venn diagram showing the area </span><span>that represents people who have a parking decal or who ride their bike to campus but who do not ride the Light Rail</span> sgaded is attached.
We know the length and width. We're just trying to find all of the area in between. To find area, we do length*width. Length is 11.5 and the width is 10.75. 11.5*10.75=123.625 ft^2
The set of integers is closed under addition, subtraction, and multiplication because when i add, subtract, or multiply any integers, the result is always an integer.
Plug in the numbers so it will turn out as 21. Divided by 3(2) . You know that if 2 numbers are close by each other than you are going to multiply so 3 times 2 = 6 , then you do 21 divided by 6 = 3.5
The answer = 3.5