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4 years ago

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The Pool Fun Company has learned that, by pricing a newly released Fun Noodle at $ 3 comma sales will reach 7000 Fun Noodles pe

r day during the summer. Raising the price to $ 4 will cause the sales to fall to 5000 Fun Noodles per day. a. Assume that the relationship between sales price, x, and number of Fun Noodles sold, y, is linear. Write an equation in slope-intercept form describing this relationship. Use ordered pairs of the form (sales price, number sold).

2 answers:

zzz [600]4 years ago

8 0

Are there any options

Effectus [21]4 years ago

8 0

Using standard linear equation, y = m*x + c

where m = slope and c = constant

putting ordered pairs, (3,7000) and (4,5000) in the above equation, we get two equations

3*m + c = 7000 and 4*m + c = 5000

On solving,

m = -2000 and c = 13000

So, the required equation is

y = -2000*x + 13000

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Please help! Very confused

aksik [14]

Answer:

A. 90

Step-by-step explanation:

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7 0

3 years ago

a women has a ladder that is 13 ft long. if she sets the base of the ladder on level ground 5ft from the side of a house, how ma

Mazyrski [523]

It is convenient to remember that 5-12-13 is a Pythagorean triple.

Her ladder is 12 ft above the ground where it rests on the house.

_____
Using the Pythagorean theorem, you are given the hypotenuse as 13 ft and one leg as 5 ft. Then the other leg is
.. √(13^2 -5^2) = √(169 -25) = √144 = 12

4 0

3 years ago

Tems11 [23]

QUESTION A

The given multiplication problem is

$\frac{39}{64} \times \frac{8}{13}$

Factor each term to obtain;

$\frac{13\times 3}{8\times8} \times \frac{8}{13}$

Cancel out the common factors to obtain;

$\frac{1\times 3}{8\times1} \times \frac{1}{1}$

Simplify to get;

$\frac{3}{8}$

QUESTION B

The given multiplication problem is

$\frac{2}{3}\times \frac{1}{5}\times \frac{4}{7}$

This the same as

$\frac{2\times 1\times 4}{3\times 5\times 7}$

This simplifies to;

$\frac{8}{105}$

QUESTION C

The given problem is

$\frac{3}{5}\times \frac{10}{12} \times \frac{1}{2}$

This is the same as

$\frac{3}{5}\times \frac{5}{6} \times \frac{1}{2}$

$=\frac{1}{1}\times \frac{1}{2} \times \frac{1}{2}$

This simplifies to

$=\frac{1}{4}$

QUESTION D.

The given expression is

$\frac{4}{9}\times 54$

Factor the 54 to obtain;

$\frac{4}{9}\times 9\times 6$

Cancel the common factors to get;

$\frac{4}{1}\times 1\times 6$

This simplifies to;

$=24$

QUESTION E

The given problem is

$20\times 3\frac{1}{5}$

Convert the mixed numbers to improper fraction to obtain;

$=20\times \frac{16}{5}$

$=4\times5 \times \frac{16}{5}$

Cancel the common factors to get;

$=4\times1 \times \frac{16}{1}$

$=64$

QUESTION F

The multiplication problem is

$11 \times 2 \frac{7}{11}$

Convert the mixed numbers to improper fractions to obtain;

$11 \times \frac{29}{11}$

Cancel out the common factors to get;

$=1 \times \frac{29}{1}$

Simplify;

$=29$

QUESTION G

The given problem is

$5\frac{1}{3}\times 5\frac{1}{8}$

Convert to improper fractions;

$=\frac{16}{3}\times \frac{41}{8}$

Cancel out the common factors to get;

$=\frac{2}{3}\times \frac{41}{1}$

$=\frac{82}{3}$

Convert back to mixed numbers

$=27\frac{1}{3}$

QUESTION H

The given expression is

$10\frac{2}{3} \times 1\frac{3}{8}$

Convert to improper fraction to get;

$\frac{32}{3} \times \frac{11}{8}$

Cancel common factors to get;

$=\frac{4}{3} \times \frac{11}{1}$

Simplify

$=\frac{44}{3}$

Convert back to mixed numbers;

$=14\frac{2}{3}$

7 0

3 years ago

The ratio of the length to the width of

tekilochka [14]

What are you trying to find out the length of

8 0

3 years ago

Charlie has 5 times as many stamps as Ryan. They have 1,608 stamps in all. How many more stamps does CHarlie have than Ryan?

Leokris [45]

So,
The ratio of Ryan to Charlie is 1:5
Ryan=x
Charlie=5x
5x+x=1608
6x=1608
Divide both sides by 6
1608/6=268
x=268
Ryan has 268 stamps.
Charlie has 5(268) 1340 stamps.
1340+268=1608
1340-268=1072.
Charlie has 1072 more stickers than Ryan.

Hope I helped!

4 0

4 years ago