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Veseljchak [2.6K]
3 years ago
7

Solve 3x2 + 13x = 10

Mathematics
1 answer:
Bas_tet [7]3 years ago
4 0
We want to solve the quadratic equation 3x² + 13x = 10.

Write the equation as
3x² + 13x - 10 = 0

Use the quadratic formula to obtain
x = (1/6) [ -13 +/- √{13² - 4*3*(-10)} ]
   = (1/6) [-13 +/- √289]
   = (1/6) [-13 +/- 17]
x = -30/6 = -5
or
x = 4/6 = 2/3

The solution is x = 2/3 and -5.

Answer:  a
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Pls solve question 4b. Verrry urgent . Ok tyy
kodGreya [7K]

Answer:

y = 3\left(x-\dfrac{3}{2}\right)^2+\dfrac{41}{4}

Step-by-step explanation:

Given equation:

y = 3x^2 - 9x + 17

Factor out 3 from the first 2 terms:

y = 3(x^2 - 3x) + 17

Divide the coefficient of x by 2 and square it:  (-3 ÷ 2)² = 9/4

Add this inside the parentheses and subtract the distributed value of it outside the parentheses:

y = 3\left(x^2 - 3x+\dfrac{9}{4}\right) + 17-\dfrac{27}{4}

Factor the parentheses and combine the constants:

y = 3\left(x-\dfrac{3}{2}\right)^2+\dfrac{41}{4}

8 0
2 years ago
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6 0
3 years ago
1. Find the value for a/b=2 But make each side have the same value.
Vladimir [108]

Step-by-step explanation:

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6 0
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Mazyrski [523]
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Then, divide ➡31 over 1 by 125


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