Answer:
This is not accurate we dont know what your asking us?
Explanation:
Answer:
See below.
Explanation:
The mass of octane in the sample of gasoline is 0.02851 * 482.6 = 13.759 g of octane.
The balanced equation is:
2C8H18(l) + 25O2(g) ----> 16CO2(g) + 18H2O(g)
From the equation, using atomic masses:
228.29 g of octane forms 704 g of CO2 and 324.3 g of H2O
So the mass of CO2 formed from the combustion of 13.759 g of octane = (704 * 13.759) / 228.29
= 42.43 g of CO2.
Amount of water = 324.3 * 13.759) / 228.29
= 19.55 g of H2O.
Answer: NOTE: MARK AS BRAINLIEST!!!!!!plz.......
15.9994
The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles Oxygen, or 15.9994 grams.
Hope that helps!!!
NOTE: MARK AS BRAINLIEST!!!!!!plz.......
I just looked it up and it says "Na2CO3 (sodium carbonate) is neither an acid nor a base. It is a salt..." I really hoped this helped you, if not I'm sorry.