We first need to find the number of moles of gas in the container
PV = nRT
where;
P - pressure - 2.87 atm x 101 325 Pa/atm = 290 802.75 Pa
V - volume - 5.29 x 10⁻³ m³
n - number of moles
R - universal gas constant - 8.314 Jmol⁻¹K⁻¹
T - temperature - 230 K
substituting these values in the equation
290 802.75 Pa x 5.29 x 10⁻³ m³ = n x 8.314 Jmol⁻¹K⁻¹ x 230 K
n = 0.804 mol
the molar mass = mass present / number of moles
molar mass of gas = 56.75 g / 0.804 mol
therefore molar mass is 70.6 g/mol
The answer is a identical
Answer : The total pressure at equilibrium is 0.350 atm
Solution : Given,
Initial pressure of
= 0.350 bar
= 0.016
The given equilibrium reaction is,

Initially 0.350 0 0
At equilibrium (0.350-2x) x x
The total pressure at equilibrium = 
Thus, the total pressure at equilibrium is 0.350 atm
Divide the number of molecules N by avogadro's constant.
Let n be the number of moles then,

Hope this helps.
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