Answer:
Molarity is halved when the volume of solvent is doubled.
Explanation:
Using the dilution equation (volume 1)(molarity 1)=(volume 2)(molarity 2), we can demonstrate the effects of doubling volume.
Suppose the starting volume is 1 L and the starting molarity is 1 M, and doubling the volume would make the final volume 2 L.
Plugging these numbers into the equation, we can figure out the final molarity.
(1 L)(1 M)=(2 L)(X M)
X M= (1 L x 1 M)/(2 L)
X M= 1/2 M
This shows that the molarity is halved when the volume of solvent is doubled.
First off, the chemical equation needs to be balanced. Since there are 2 oxygen atoms in the reactants, we must produce 2 moles of MgO, which means we need 2 moles of Mg, giving:
2Mg + O2 --> 2MgO
Therefore for a stoichiometric reaction where no reactant is left over, the number of moles of magnesium must be double that of oxygen. However, as seen, the molar ratio of magnesium to oxygen is 2:5, meaning oxygen is in large excess, and Magnesium is the limiting reactant. Therefore the answer is A.
The answer is false. It is because the electron structure of
the atom is not determined by using the direct observation of using an x-ray
but rather the usage of theoretical modeling and the emission spectra will be useful
in observing.
When titrating a strong monoprotic acid and KOH at 25 degrees Celcius, the pH will be approximately equal to 7.00. Since a strong acid and a strong base reacts through a neutralization reaction. The pH of a neutral solution is 7.00. <span />
Some people weren't convinced with the theory. Also many people tried to prove that the atom didn't exist, or at least prove the theory wrong.
