<span> tan(x)/ cos(x)-sec(x)
tanx/(cosx-1/cosx)
tanx/cos^2x-1)--------------------1-sin^2x=cos^2x
-tanx/sin^2x
-(sinx/cosx)/sin^2x
-1/sinxcosx
multiply 2/2
-2/2sinxcosx-------------sin2x=2sincosx
-2/sin2x------------------1/sinx=cosecx
-2cosec2x</span>
Answer:
17
Step-by-step explanation:
It would be 34.34
Hope this helps! :)
You must find the relative rates of both workers...
T=f/3 and J=f/2 so if they work together to clear the field then:
ft/3+ft/2=f make all terms have a common denominator of 6
(2/2)(ft/3)+(3/3)(ft/2)=(6/6)f
2ft/6+3ft/6=6f/6 multiply both sides by 6
2ft+3ft=6f divide both sides by f
2t+3t=6 combine like terms on left side
5t=6 divide both sides by 5
t=6/5 hr
t=1 1/5 hr
t=1 hr 12 min
First we need to find the probability of selecting the 1 blue marble out of the 20 marbles total, which is 1/20.
Next, we need to find the probability of tossing the fair coin so it lands tails up, which is 1/2.
To find the probability of both events happening, we need to multiply the probabilities of the two individual events:
1/20 * 1/2 = 1/40
So the answer is 1/40, or 2.5%
Sorry about the poor formatting :( I'm on my phone at the moment, which makes it difficult.
Hope I helped, and let me know if you have any questions :D
