Quadratic Equations in Single Variable
n²-3n+10=0
2x²+2x+1=0
25b²-16=0
f²-3f+2=0
1/3m +2m=4
a²=225
Linear Equation in single Variable
8-3k=12
5w+5=0
10u-5=8
Linear Equation in Two Variable
2y-z=9
3r+2e=6
d=3e-7
<h3>What is an equation?</h3>
It should be noted that an equation simply means the expression that's used to show the relationship between the variables.
In this case, the equation has been grouped.
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Group the given equations into two based on observed common properties.
Equations
n²-3n+10=0
8-3k=12
2y-z=9
2x²+2x+1=0
25b²-16=0
3r+2e=6
5w+5=0
f²-3f+2=0
d=3e-7
1/3m +2m=4
10u-5=8
a²=225
Answer:
1 and 3, 2 and 4
Step-by-step explanation:
Supplementary angles total to 180° or should form a straight line. 1 and 3, 2 and 4 are vertical angles which equal one another and are not supplementary.
Answer:
2.2 metres squared
Step-by-step explanation:
We need to find the area of this trapezoid.
The area of a trapezoid is denoted by:
, where
and
are the parallel bases and h is the height
Here, we already know the lengths of the two bases; they are 0.9 metres and 2.3 metres. However, we need to find the length of the height.
Notice that one of the angles is marked 45 degrees. Let's draw a perpendicular line from top endpoint of the segment labelled 0.9 to the side labelled 2.3. We now have a 45-45-90 triangle with hypotenuse 2.0 metres. As one of such a triangle's properties, we can divide 2.0 by √2 to get the length of both legs:
2.0 ÷ √2 = √2 ≈ 1.414 ≈ 1.4
Thus, the height is h = 1.4 metres. Now plug all these values we know into the equation to find the area:


The answer is thus 2.2 metres squared.
<em>~ an aesthetics lover</em>
Answer:
1 1/4 yards of fabric
Step-by-step explanation:
2 1/2+ 1 3/4=4 1/4
4 1/4 - 3 = 1 1/4
The number of the specimens would be in the culture after 5 minutes will be 7,962.62.
<h3>What is an exponent?</h3>
Consider the function:
y = a (1 + r) ˣ
Where x is the number of times this growth occurs, a = initial amount, and r = fraction by which this growth occurs.
A bacteria culture grows at a rate of 20% per minute.
If the culture initially has 3,200 bacteria specimens.
Then the equation will be
y = 3200 (1 + 0.2) ˣ
y = 3200 (1.20) ˣ
Then the number of the specimens would be in the culture after 5 minutes will be
y = 3200 (1.20)⁵
y = 7962.62
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