Answer:
Chuck's rate of travel = 63mph
Step-by-step explanation:
Given chuck travels 252 miles and dana travels 228 miles. Given that they both take same time to travel .
Let the travelling time be T.
Also given that the speed of chuck is 6mph greater than that of dana's.
let the speed of chuck be x. Now
Speed = 
x= 
Now for Dana's speed
x-6= 
When we divide both the equations we get
x=63mph
The best way to solve a problem like this is to set up two equations. First assign a variable to each thing you are trying to find. In this case, it's two different kinds of cars. Let's call the cars that weigh 3,000 pounds x, and the ones that weigh 5,000 y. The two equations you should write are:
x+y=18 (because the problem tells you there were 18 cars in total)
3000x+5000y=60000 (because that is the total weight in the problem)
Next, you need to solve for one of the variables. I will solve for x first by subtracting y from both sides of the first equation.
x=18-y
Then you have to plug that into the other equation to get:
3000(18-y)+5000y=60000
Simplify and solve for y:
54000-3000y+5000y=60000
54000+2000y=60000
2000y=6000
y=3
Now that you know what y equals, you can put it into the equation we solved for x:
x=18-3
x=15
So there are 15 cars that weigh 3000 pounds and 3 that weigh 5000.
The answer would be 6ft and the reason why is because the shed
1,000,000/50=20,000 so 20,000 50-passenger buses. Hope this helped!
Find the mean, median, and mode for 0, 4, 6, 11, 9, 8, 9, 1, 5, 9, 7. Round to the nearest tenth if needed.
masha68 [24]
The mean is 6
The median is 8
and the mode is 9 hope this helps!
