Ask question

Ask question

All categories

3 years ago

7

Reduce ratio 49:21 to lowest form

2 answers:

mafiozo [28]3 years ago

7 0

$\bf 49:21\implies \cfrac{49}{21}\implies \cfrac{7\cdot 7}{3\cdot 7}\implies \cfrac{7}{3}\cdot \cfrac{7}{7}\implies \cfrac{7}{3}\cdot 1\implies \cfrac{7}{3}\implies 7:3$

Strike441 [17]3 years ago

7 0

7 over 3 . Because you find the LCD for both numbers which is 7 and what you do to the top you do to the bottom . 49 divided by 7 is 7 and 21 divided by 7 is 3 and you cant simplify that any lower so the answer is 7 over 3

You might be interested in

What is this? (2 photos please look and just answer A, B, or C)

igomit [66]

I think the answer is C

7 0

2 years ago

Read 2 more answers

The point is plotted on the number line.What whole number best approximates the value of x?

sattari [20]

You can eliminate 81 because we know $\sqrt{81} =9$

The dot is on approximately 9.32 (my estimate) so I would square that number:

(9.32)² = 86.8624 so if you round this you get 87

6 0

3 years ago

Read 2 more answers

What is this answer?

zhuklara [117]

Answer:

B is the correct answer

3 0

2 years ago

The length of a 200 square foot rectangular vegetable garden is 4feet less than twice the width. Find the length and width of th

inna [77]

Answer:

Length = 18.099 ft

Width = 11.049 ft

Step-by-step explanation:

let the length of the field be x ft

and the width be y ft

as per the condition given in problem

x=2y-4 -----------(A)

Also the area is given as 200 sqft

Hence

xy=200

Hence from A we get

y(2y-4)=200

taking 2 as GCF out

2y(y-2)=200

Dividing both sides by 2 we get

$y(y-2)=100$

$y^2-2y=100$

subtracting 100 from both sides

$y^2-2y-100=0$

Now we solve the above equation with the help of Quadratic formula which is given in the image attached with this for any equation in form

$ax^2+bx+c=0$

Here in our case

a=1

b=-1

c=-100

Putting those values in the formula and solving them for y

$y=\frac{-(-2)+\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}$

$y=\frac{-(-2)-\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}$

Solving first

$y=\frac{2+\sqrt{4+400}{2}$

$y=\frac{2+\sqrt{404}{2}$

$y=\frac{2+20.099}{2}$

$y=\frac{22.099}{2}$

$y=11.049$

Solving second one

$y=\frac{-(-2)-\sqrt{(-2)^2-4 \times (-1) \times 100}}{2 \time 1}$

$y=\frac{2-\sqrt{4+400}{2}$

$y=\frac{2-\sqrt{404}{2}$

$y=\frac{2-20.099}{2}$

$y=\frac{-18.99}{2}$

$y=-9.045$

Which is wrong as the width can not be in negative

Our width of the field is

y=11.099

Hence the length will be

x=2y-4

x=2(11.049)-4

x=22.099-4

x=18.099

Hence our length x and width y :

Length = 18.099 ft

Width = 11.049 ft

4 0

3 years ago

ABCD Is a parallelogram if m

Viefleur [7K]

Step-by-step explanation:

ABC+DAB=180

DAB=180-115

DAB= 65

m<3+m<4=65

m<3=65-m<4

You have been given 4 degrees there, but it has not fallen. The answer is either A or B. Subtracting the conditional degree from 65. Find 3.

7 0

3 years ago

Read 2 more answers