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dedylja [7]
3 years ago
10

What is the domain and range of f(x)=2|x-4|

Mathematics
1 answer:
Natali5045456 [20]3 years ago
8 0
Domain is all the numbers you can use for x, it's the input
range is the numbers you get from inputting the domain, it's te output



we can use all real numbers because no square roots of negatives or division of zero occur

domain is all real numbers

notice that when x goes to positive infinity, f(x) goes to positive infinity
when x goes to negative inifnity, f(x) goes to positive inifinty
but, as x approaches 4, the value of f(x) approaches 0

the lowest point on range is 0 and max is negative infinity


domain=all real numbers
range= from 0 to infinity
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Step-by-step explanation:

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Suppose that the sitting​ back-to-knee length for a group of adults has a normal distribution with a mean of mu equals 24.4 in.
solong [7]

Answer:

P(X \geq 26.6) = 0.0336, which is greater than 0.01. So a back-to-knee length of 26.6 in. is not significantly high.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 24.4, \sigma = 1.2

In this problem, a value x is significantly high if:

P(X \geq x) = 0.01

Using these​ criteria, is a​ back-to-knee length of 26.6 in. significantly​ high?

We have to find the probability of the length being 26.6 in or more, which is 1 subtracted by the pvalue of Z when X = 26.6. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{26.6 - 24.4}{1.2}

Z = 1.83

Z = 1.83 has a pvalue of 0.9664.

1 - 0.9664 = 0.0336

P(X \geq 26.6) = 0.0336, which is greater than 0.01. So a back-to-knee length of 26.6 in. is not significantly high.

6 0
3 years ago
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