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3 years ago

Let f (x)=x^2+2x-35 enter the x-intercepts of the quadratic function in the boxes and_

Mathematics

2 answers:

valina [46]3 years ago

4 0

Hello :
the x-intercepts of the quadratic when :
x²-2x-35 =0
(x-7)(x+5) =0
x-7=0 or x+5=0
x=7 or x= -5

serious [3.7K]3 years ago

3 0

Answer:

The x-intercepts of the quadratic function are -7 and 5.

Step-by-step explanation:

The given function is

$f(x)=x^2+2x-35$

Equate f(x)=0, to find the x-intercepts of the function.

$x^2+2x-35=0$

$x^2+7x-5x-35=0$

$x(x+7)-5(x+7)=0$

$(x+7)(x-5)=0$

$x+7=0\Rightarrow x=-7$

$x-5=0\Rightarrow x=5$

Therefore the x-intercepts of the quadratic function are -7 and 5.

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What is the midpoint of CD? • (1/2,-5/2) •(1,-5/2) •(1/2,-3/2) •(1,-3/2)

polet [3.4K]

Answer:

(1/2,-5/2)

Step-by-step explanation:

$\frac{ - 3 + 4 }{2} = \frac{1}{2} \\ \frac{ - 4 + - 1}{2} = \frac{ - 5}{2}$

7 0

3 years ago

Read 2 more answers

The length of a rectangle 4 yd is longer than its width. If the perimeter of the rectangle is 68 yd, find its length and width.

natulia [17]

w + 4

------------------------

l l

l l w

l l

------------------------

Perimeter would be the sum of all the sides so: (w+4) + w + (w+4) + w

Perimeter is 60 yards according to your problem so: (w+4) + w + (w+4) + w = 60 yds

1.Simplify/combine like terms:

w + 4 + w + w + 4 + w =

4w + 8 =

Now it's a 2-step algebra equation

4w + 8 = 60

2.Subtract 8 on both sides

4w = 56

3.Divide both sides by 4

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4 0

3 years ago

Find the four rational numbers and irrational numbers between 2/5 and 5/6

Savatey [412]

The four?

Of course there are an infinite number of rationals between any two different real numbers, as well as an even bigger infinite number of irrationals.

The average will be between the numbers:

$\frac 1 2 (\frac 2 5 + \frac 5 6) = \dfrac{37}{60}$

That's a lot of work to get a number in between. We can just see

$\frac 1 2$
is between the two numbers.

The mediant, or freshman addition, will always be in between:

$\dfrac{2 + 5}{5 + 6} = \dfrac{7}{11}$

2/5=.4 and 5/6 is about .83, so

$.6 = \frac{6}{10}$

is in between as is .7, .41, .530940394 and as many rationals as we care to generate.

To get irrationals we could just add a teeny irrational to the ones we just generated, like $\frac{6}{10} + \frac{\pi}{100}$

We could just change that denominator a bit and get as many as we like.

But let's get some square roots. The geometric mean will be between

$\sqrt{ \dfrac 2 5 \cdot \dfrac 5 6 } = \dfrac{1}{\sqrt{3}}
$

That's the tangent from one of trig's biggest cliches, but I digress. It's in between.

While we're on trig cliches,

$\dfrac{1}{\sqrt{2}}$

is in between as well.

Keeping with the trig theme, also in between are

$\dfrac{\pi} 6$

and

$\dfrac{\pi}{4}$

the angles associated with the some of the above trig function values.

We could obviously go on as long as we cared to.

7 0

3 years ago

Please help! what’s the value of x? 8 56 12 62

Katyanochek1 [597]

The value of x is 56

4 0

3 years ago

The standard normal curve shown below models the population distribution of a random variable. What proportion of the values in

patriot [66]

About 32.34% of the values do not lie between the z-scores of -1.3 and 0.75.

First, we need to find the region between the z-scores.

If you look at a normal distribution table, you will get the following values:

0.75 = 77.34%
-1.3 = 9.68%

Subtraction those gives us the area between the z-scores.
77.34 - 9.68 = 67.66%

Now, just subtract that value from 100% to get the amount outside of the area.
100 - 67.66 = 32.34%

4 0

3 years ago

Let f (x)=x^2+2x-35 enter the x-intercepts of the quadratic function in the boxes __and___

Let f (x)=x^2+2x-35 enter the x-intercepts of the quadratic function in the boxes and_