Question

Let f (x)=x^2+2x-35 enter the x-intercepts of the quadratic function in the boxes __and___

Answer 1

Hello :
the x-intercepts of the quadratic  when : 
x²-2x-35 =0
(x-7)(x+5) =0
x-7=0   or  x+5=0
x=7 or  x= -5

Answer 2

Answer:

The x-intercepts of the quadratic function are -7 and 5.

Step-by-step explanation:

The given function is

$f(x)=x^2+2x-35$

Equate f(x)=0, to find the x-intercepts of the function.

$x^2+2x-35=0$

$x^2+7x-5x-35=0$

$x(x+7)-5(x+7)=0$

$(x+7)(x-5)=0$

$x+7=0\Rightarrow x=-7$

$x-5=0\Rightarrow x=5$

Therefore the x-intercepts of the quadratic function are -7 and 5.