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irina [24]
2 years ago
7

Which sum does not equal ? 7/8

Mathematics
1 answer:
Drupady [299]2 years ago
7 0

The sum which is not equal to 7/8 is 7/8 +7/8 = 14/8

Given,

a) 2/8 + 5/8 = 7/8 which is equal to 7/8.

Therefore, option a) is incorrect.

b) 1/8 + 6/8 = 7/8, which  is also equal to 7/8.

Option b) is also incorrect.

c) 7/8 + 7/8 = 14/8 , which is not equal to 7/8.

Hence option c) is correct.

d) 3/8 + 4/8 = 7/8, which is equal to 7/8.

Option d) is also incorrect.

Hence option c) is correct as it matches the conditions of the question.

7/8 + 7/8 = 14/8 is not equal to 7/8.

To learn more about the sum, visit: brainly.com/question/2059515

#SPJ9

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A - g(x) = |x-5|+5 <br> B - g(x) = |x-5| <br> C - g(x) = |x|+5 <br> D - g(x) = |x+5|+5
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Answer:

g(x) =  |x|  + 5

Step-by-step explanation:

Since both the original and transformed graph have the same x value for their vertex, there was no horizontal shift. However the vertex shifted up. Specifically it shifted up 5 units. Therefore:

g(x) = f(x) + 5

The plus 5 performs a translation up 5 units. Plugging in for f(x) it can be seen that:

g(x) =  |x|  + 5

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In the next step of the derivation, we passed a horizontal plane through the sphere b up from the center. We let the radius of t
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Step-by-step explanation:

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7 0
3 years ago
A safety officer wants to prove that μ = the average speed of cars driven by a school is less than 25 mph. Suppose that a random
Akimi4 [234]

Answer:

t=\frac{24-25}{\frac{2.2}{\sqrt{14}}}=-1.70    

The degrees of freedom are given by:

df=n-1=14-1=13  

The p value for this case would be given by:

p_v =P(t_{(13)}  

Step-by-step explanation:

Information given

\bar X=24 represent the mean height for the sample  

s=2.2 represent the sample standard deviation

n=14 sample size  

\mu_o =25 represent the value that we want to test

t would represent the statistic

p_v represent the p value for the test

Hypothesis to verify

We want to cehck if the true mean is lees than 25 mph, the system of hypothesis would be:  

Null hypothesis:\mu \geq 25  

Alternative hypothesis:\mu < 25  

The statistic would be given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Replacing the info given we got:

t=\frac{24-25}{\frac{2.2}{\sqrt{14}}}=-1.70    

The degrees of freedom are given by:

df=n-1=14-1=13  

The p value for this case would be given by:

p_v =P(t_{(13)}  

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