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Step-by-step explanation:
Numbers may be formed with or without the repetition of digits. Let us observe some of the formation of numbers without the repetition of digits. But with the digit 0 and the digit 6, only the number 60 is formed.
Simple...
you have: 5(x+5)<85
Simplify it-->>(Distribute the 5)
5(x+5)<85
5x+25<85
5x+25<85
-25 -25
5x<60
x<12
Thus, your answer.
Answer:
The answer is C
Step-by-step explanation:
got it right on edge
If you're just factorizing, you can do so by grouping.
cot³(x) + cot²(x) + cot(x) + 1
= cot²(x) (cot(x) + 1) + cot(x) + 1
= (cot²(x) + 1) (cot(x) + 1)
Put another way, if y = cot(x) + 1, then
cot²(x) y + y = (cot²(x) + 1) y
We can simplify this somewhat. Recall the Pythagorean identity,
sin²(x) + cos²(x) = 1
Dividing through both sides of the equation by sin²(x) reveals another form of the identity,
sin²(x)/sin²(x) + cos²(x)/sin²(x) = 1/sin²(x)
1 + cot²(x) = csc²(x)
Then we end up with
cot³(x) + cot²(x) + cot(x) + 1 = csc²(x) (cot(x) + 1)
