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fomenos
3 years ago
6

A constant force F=47i+30j moves an object along a vector D=13i-8j. find the work done

Mathematics
2 answers:
Nikitich [7]3 years ago
3 0
W=(47\,\mathbf i+30\,\mathbf j)\cdot(13\,\mathbf i-8\,\mathbf j)=371
WINSTONCH [101]3 years ago
3 0

Answer: The correct answer is 371 J.

Step-by-step explanation:

The expression for work done in terms of force and displacement is as follows;

W=F.D

Here, F is the applied force and D is the displacement.

Here, the work done is equal to the dot product of force and displacement. The dot product of i.i=j.j=k.k=1.

Calculate the work done.

W=F.D

Put F=47i+30j and D=13i-8j.

W=(47i+30j).(13i-8j)

W=611-240

W= 371 J

Therefore, the work done is 371 J.

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Ede4ka [16]
We have the rational expression \frac{2x^{5}-6x^{2}+4x4y}{2x}; to simplify it, we are going to try to find a common factor in the numerator, and, if we are luckily, that common factor will get rid of the denominator 2x.
Notice that in the denominator all the numbers are divisible by two, so 2 is part of our common factor; also, all the terms have the variable x, and the least exponent of that variable is 1, so x will be the other part of our common factor. Lets put the two parts of our common factor together to get 2x.
Now that we have our common factor, we can rewrite our numerator as follows:
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3 years ago
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3 years ago
A spotlight on the ground shines on a wall 12 m away. If a man 2 m tall walks from the spotlight toward the building at a speed
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Answer:

The length of shadow decrease at 0.48 m/s.

Step-by-step explanation:

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Now solve for the dy/dt when x=4

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\frac{2}{12-x} = \frac{y}{12} \\Y = \frac{24}{12 - x} \\ \frac{dy}{dt} = \frac{24}{(12-x)^{2}} \times \frac{dx}{dt} \\at x=4, dy/dt \ becomes: \\\frac{24}{(12-4)^2} \times -1.3 \\= -0.48 m/s

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