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LenaWriter [7]
3 years ago
8

I need help setting up the limits of integration for part A please. I need to get the mass.

Mathematics
2 answers:
Dafna1 [17]3 years ago
8 0

l

o o

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never [62]3 years ago
5 0
Nene did. Did d do e ele e iré
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Pls answer will get brainliest!!!
crimeas [40]
By using The half-angle formula

cos X/2 = ±√[(1 + cos X)/ 2]
But we have cos x=2/3
= ±√[(1 + 2/3)/ 2]
= ±√[(5/3 )/ 2]
= ±√[(5/5]
=±√1

Therefore answer is ±1

cos A/2 = ±√[(1 + cos A )/ 2]
3 0
3 years ago
Four hundreths in number form
Sonja [21]
.04 Im pretty sure this is the answer
4 0
4 years ago
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If function g has the factors (x − 7) and (x 6), what are the zeros of function g?
antiseptic1488 [7]
The second one isn’t a factor… if you meant (x+6) then the two zeros are 7 and -6
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2 years ago
PLZZZ HELP  A student solved this problem by making a table. Jules bought a scarf and a patch for each of the 8 summer campers i
sergeinik [125]
Day 1:
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4 0
4 years ago
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What else would need to be congruent to show that JKL= MNO by AAS?
taurus [48]
Answer: Choice B) Angle L = Angle O

---------------------------------------------------
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If we know that Angle L is congruent to Angle O, then we can use the AAS (angle angle side) congruence property. We have one pair of angles marked by the square marker (angle J and angle M). So they are congruent angles. We have a pair of congruent sides JK = MN = 3. So we're just missing a pair of angles. 

Note: The answer is NOT angle K = angle N because this would mean ASA would be used instead of AAS. The order of the letters is important as it establishes how the sides and angles relate. With ASA, the side is between the angles. With AAS, the side is not between the angles. 

3 0
3 years ago
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