Answer:
ill start figuring it out now luv <3
Step-by-step explanation:
Answer: B. 0.4772
Step-by-step explanation:
Given : The mean time : 
Standard deviation : 
Let X be the service time of a randomly selected customer.
Assuming a normal distribution, the value of z-score is given by :-

For x = 64

For x = 100

The p-value =

Hence, the probability that a randomly chosen customer experiences service done between 64 and 100 minutes = 0.4772
The particular construction used will make OS the angle bisector of ∠POQ, so
.. ∠POS = (1/2)*∠POQ.
This is true for selection C.