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3 years ago

13

Paul's math teacher has several workbooks she wants to place them on a bookshelf but needs to know if they were all fit in one s

helf The thickness and number workbooks is shown on the line plot.

2 answers:

Tresset [83]3 years ago

8 0

Answer:

5 and 4/8

Step-by-step explanation:

you use math to solve it.

satela [25.4K]3 years ago

7 0

Answer:

uhhhhhh I think it's a uhhhhhh carrot

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What value of x is in the solution set of 8x – 6 > 12 + 2x?

Harman [31]

Answer:

$8x - 6 > 12 + 2x \\ 8x - 2x > 12 + 6 \\ 6x > 18 \\ \frac{6x}{6} > \frac{18}{6} \\ x > 3$

<em>hope</em><em> </em><em>this</em><em> </em><em>helps</em><em> </em><em>you</em><em>.</em><em>.</em><em>.</em><em>!</em>

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2 years ago

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A hat's original price was $50. It is on sale for 40%0ff. How much does it cost?

yKpoI14uk [10]

Answer:

30

Step-by-step explanation:

40/100 x 50= 20

50-20=30

3 0

2 years ago

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Choose the correct answer from the given four options:In an AP if a = –7.2, d = 3.6, an = 7.2, then n

Serggg [28]

Answer:

n=5

Step-by-step explanation:

by using

n=(an-a)/a+1

substituting values

n= 7.2-(-7.2)/3.6 +1

n=5

5 0

3 years ago

Determine the zeroes of the polynomial

Anna71 [15]

Answer:

3,7/6

Step-by-step explanation:

$(\sqrt{x^2-4x+3} )+(\sqrt{x^{2} -9} )-(\sqrt{4x^2-14x+6} )\\=(\sqrt{x^2-x-3x+3} )+(\sqrt{(x^2-3^2})-(\sqrt{4x^2-2x-12x+6})\\ =(\sqrt{x(x-1)-3(x-1)} )+\sqrt{(x+3)(x-3)}-\sqrt{2x(2x-1)-6(2x-1)} \\=\sqrt{(x-1)(x-3)}+\sqrt{(x+3)(x-3)} -\sqrt{2(2x-1)(x-3)} \\=\sqrt{x-3} (\sqrt{x-1} +\sqrt{x+3} -\sqrt{2(2x-1)} )\\$

$\sqrt{x-3} =0~gives~x=3\\or~\sqrt{x-1} +\sqrt{x+3} -\sqrt{2(2x-1)} =0\\or~ \sqrt{x-1} +\sqrt{x+3} =\sqrt{2(2x-1)} \\squaring\\x-1+x+3+2\sqrt{x-1} \sqrt{x+3} =2(2x-1)\\2x+2+2\sqrt{(x-1)(x+3)} =4x-2\\2\sqrt{x^2-x+3x-3} =2x-4\\\sqrt{x^2+2x-3} =x-2\\again ~squaring\\x^2+2x-3=x^2-4x+4\\\\2x+4x=4+3\\6x=7\\x=\frac{7}{6}$

8 0

3 years ago

What is the polynomial function of least degree whose only zeros are -3, ,-2, and 4 ?

victus00 [196]

Answer: (x³ - 2x² - 11x + 12)

Step-by-step explanation:

Recall that zeroes can be transformed into factors by subtracting them from x. This gives us the following factors:

(x - 1)(x + 3)(x - 4)

Now, if you multiply the first two factors together, you get the following:

(x² + 2x - 3)

Multiply that by the last factor, (x - 4), and you get this:

(x³ + 2x² - 3x - 4x² - 8x + 12)

This can be simplified:

(x³ - 2x² - 11x + 12)

And there's your final answer. Hope this helped! (x³ - 2x² - 11x + 12)

7 0

3 years ago