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3 years ago

Which graph represents -

Mathematics

1 answer:

11Alexandr11 [23.1K]3 years ago

5 0

Answer:

3rd

Step-by-step explanation:

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Fraction 4 over 5n = Fraction 2 over 3. n = ___? Fraction 2 over 15 Fraction 5 over 6 1Fraction 1 over 5 1Fraction 7 over 15

podryga [215]

N=1.2 I don't know what you are asking in the second part of the question

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3 years ago

How many times greater is the vuale in 4 in 547 than 4 in 84

sineoko [7]

Answer:

10 times

Step-by-step explanation:

4 in 547 is equal to 40

4 in 84 is equal to 4

When you separate that number into smaller parts

Ex: 547 = 500 + 40 + 7

6 0

3 years ago

Ariel invests $3,000 in an account that pays him 5% interest, compounded annually. How much money will Ariel have in the account

ozzi

Answer:

5,120

Step-by-step explanation:

5 0

3 years ago

Greta reads 2 books each month as part of her book club. If Greta has read 32 books so far, how many months has she been with he

igomit [66]

Given data:

The numbers of books read by Greta are 2.

The expression for the given statement is,

1 month = 2 books

Multiply the above expression by 16 onn both sides.

16(1 month)=16(2 books)

16 months= 32 books

Thus, 32 books read by Greta in 16 months.

7 0

2 years ago

Plot the points A(9, 11) and B(–3, –5). Find midpoint M of AB. Then show that AM = MB and AM + MB =AB

Alex_Xolod [135]

Answer:

The midpoint is (3, 3).

Step-by-step explanation:

We are given the two points A(9, 11) and B(-3, -5).

The midpoint is given by:

$\displaystyle M=\Big(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}\Big)$

So:

$\displaystyle M = \Big( \frac{9+(-3) }{2}, \frac{ 11+(-5) }{2} \Big) = (3,3)$

The midpoint is (3, 3).

We want to show that AM = MB.

We can use the distance formula:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2$

The distance between A(9, 11) and M(3, 3) will then be:

$AM=\sqrt{(9-3)^2+(11-3)^2}=\sqrt{6^2+8^2}=\sqrt{100}=10$

And the distance between B(-3, -5) and M(3, 3) will be:

$MB = \sqrt{ (3-(-3))^2 + (3-(-5))^2 } = \sqrt{(6)^2+(8)^2} = \sqrt{ 100 } = 10$

So, AM = MB = 10.

Since AM = MB = 10, AM + MB = 10 + 10 = 20.

So, we want to prove that AB = 20.

By the distance formula:

$AB=\sqrt{(9-(-3))^2+(11-(-5))^2}=\sqrt{12^2+16^2}}=\sqrt{400}=20\stackrel{\checkmark}{=}20$

4 0

3 years ago