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nlexa [21]
3 years ago
15

(03.02)

Mathematics
1 answer:
777dan777 [17]3 years ago
4 0

Answer:

To provide a situation of 1 and O, here is a situation

Step-by-step explanation:

The acceleration would be 1.  

If the acceleration is 10 m/s, the object will gain more speed.

On the other hand, if the acceleration is -10m/s, then the object will lose speed.

In the case of 1, the object gained more speed, in the case of 0, the object will lose speed.

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Sarah answered 24 questions on her test correctly and earned an 80%. How many questions were on the test?
MaRussiya [10]

Answer:

43 questions in total

Step-by-step explanation:

the original equation with the unknown (total number of questions on the test) will look like this

\frac{total \: number \: of \: questions \: on \: exam}{24 \: answered \: questions}  = 80\%

we know this because to work out a percentage in the 1st place you need the total ÷ number (in this case it's ÷ how many questions out of the total she did answer)

now you rearrange.

you need to move the 24 to get the total on it's own here's how you do it

\frac{tot \: num \: of \: qs}{24}  \times 24 = 80\% \times 24

what you do to one side of equation you have to do to the other. the 24 and 24 on the left will cancel because 24÷24=1 and we don't write

got mum of Q's x 1= 80 x 24

now you convert % to decimal

80\% \times 100 = 0.80

replace

tot \: num \: qs \:  = 24 \times 0.80 = 19

now you take the original and + the 19

24 + 19 = 43

therefore there are a total of 43 questions on the exam

5 0
4 years ago
Find the value of x such that 365 based seven + 43 based x = 217 based 10.
Pepsi [2]

We need to find the base x in the following equation:

365_7+43_x=217_{10}

First, lets convert 365 from base 7 to base 10. This is given by

365_7=3\times7^2+6\times7^1+5\times7^0

where the upperindex denotes the position of eah number. This gives

\begin{gathered} 365_7=3\times49+6\times7+5\times1 \\ 365_7=147+42+5 \\ 365_7=194_{10} \end{gathered}

that is, 365 based 7 is equal to 194 bases 10.

Now, lets do the same for 43 based x. Lets convert 43 based x to base 10:

43_x=4\times x^1+3\times x^0

where again, the superindex 0 and 1 denote the position 0 and 1 in the number 43. This gives

43_x=(4x+3)_{10}

Now, we have all number in base 10. Then, our first equation can be written in base 10 as

194_{10}+(4x+3)_{10}=217_{10}

For simplicity, we can omit the 10 and get

194+4x+3=217

so, we can solve this equation for x. By combining similar terms. we have

197+4x=217

and by moving 197 to the right hand side, we obtain

\begin{gathered} 4x=217-197 \\ 4x=20 \end{gathered}

Finally, we get

\begin{gathered} x=\frac{20}{4} \\ x=5 \end{gathered}

Therefore, the solution is x=5

8 0
1 year ago
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