Answer:
B. 9x10^4
Step-by-step explanation:
Answer:
27.4
Step-by-step explanation:
First multiply the numerator and denominator by 10
Then write the problem in long division format
Then divide 52 by 19 and get 2
Then multiply the quotient digit (2) by the divisor 19
Then subtract 38 from 52
Then bring down the next number of the dividend
Then divide 140 by 19 to get 7
Then multiply the quotient digit (7) by the divisor 19
Then subtract 133 from 140
Then add a decimal point to the solution
Then bring down the next number of the dividend
Then divide 76 by 19 to get 4
Then multiply the quotient digit (4) by the divisor 19
Then subtract 76 from 76
The solution for long division for 52.06./1.9 is 27.4
27.4
Answer:
2
Step-by-step explanation:
By using the concept of uniform rectilinear motion, the distance surplus of the average race car is equal to 3 / 4 miles. (Right choice: A)
<h3>How many more distance does the average race car travels than the average consumer car?</h3>
In accordance with the statement, both the average consumer car and the average race car travel at constant speed (v), in miles per hour. The distance traveled by the vehicle (s), in miles, is equal to the product of the speed and time (t), in hours. The distance surplus (s'), in miles, done by the average race car is determined by the following expression:
s' = (v' - v) · t
Where:
- v' - Speed of the average race car, in miles per hour.
- v - Speed of the average consumer car, in miles per hour.
- t - Time, in hours.
Please notice that a hour equal 3600 seconds. If we know that v' = 210 mi / h, v = 120 mi / h and t = 30 / 3600 h, then the distance surplus of the average race car is:
s' = (210 - 120) · (30 / 3600)
s' = 3 / 4 mi
The distance surplus of the average race car is equal to 3 / 4 miles.
To learn more on uniform rectilinear motion: brainly.com/question/10153269
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Answer:
-18
Step-by-step explanation:
5a2-7-b3
Therefore, -18 is your answer.
Hope this helped! :)
