<span>Answer:
Its too long to write here, so I will just state what I did.
I let P=(2ap,ap^2) and Q=(2aq,aq^2)
But x-coordinates of P and Q differ by (2a)
So P=(2ap,ap^2) BUT Q=(2ap - 2a, aq^2)
So Q=(2a(p-1), aq^2)
which means, 2aq = 2a(p-1)
therefore, q=p-1
then I subbed that value of q in aq^2
so Q=(2a(p-1), a(p-1)^2)
and P=(2ap,ap^2)
Using these two values, I found the midpoint which was:
M=( a(2p-1), [a(2p^2 - 2p + 1)]/2 )
then x = a(2p-1)
rearranging to make p the subject
p= (x+a)/2a</span>
Answer:
Cuboid
Step-by-step explanation:
Answer: A false, B true, C true
Step-by-step explanation:
A) intercept with y axis
That means x=0
y= 3*0-2
y= -2 So A is false
B) intercept with x axis
That means y=0
0= 3x-2
2=3x
2/3= x B is true
C) The form of linear function is
f(x)= mx +n, where m is the slope
In this case m= 3 so C is true
