DUE SOON !!!!!!!! Please HELP !!!!!!!!! Will mark BRIANLIEST !!!!!!!!!!!!!!

To find the distance between (17,3) and (17,−5), Marcia used the following equation. Is Marcia correct? Explain. D=|3−(−5)|=8

Bumek [7]

Answer:

Step-by-step explanation:

The formula for finding the distance between two points is expressed as shown

D = √(x₂-x₁)²+(y₂-y₁)²

Given the coordinate (17,3) and (17,−5), from the coordinates x₁ = 17, y₁ = 3, x₂ = 17 and y₂ = -5.Substituting the values given into the formula;

D = √(17-17)²+(-5-3)²

D = √0²+(-8)²

D = √64

D = 8

According to the result gotten, it can concluded that Marcia is correct although she didn't use the right expression to calculate her distance. She should have taken the square root of the sum of the square of difference in the coordinates axis according to the formula used.

8 0

3 years ago

Find the equation of the circle with a diameter whose end points are (-1,-2) and (-3,2)

Sergeeva-Olga [200]

Answer:

The equation of the circle with a diameter whose end points are (-1,-2) and (-3,2) is

$x^{2} +y^{2}+4x-1=0$

Step-by-step explanation:

Explanation:-

Step 1:-

The equation of the circle having center and radius is

$(x-h)^2+(y-k)^2=r^2$

here center is (h,k) and radius is r

Given diameter whose end points are (-1,-2) and (-3,2)

The diameter of the circle is passing through the center of the circle

so center of the circle = midpoint of two end points

$(\frac{-1 +(-3) }{2} ,\frac{-2+2 }{2} )$

$(-2,0)$

therefore center (h,k) = (-2,0)

Step 2:-

we have to find the radius of the circle

the radius of the circle = the distance from center to the one end point

i.e., C P = r

Given one end point is P(-3,2) and center C(-2,0)

The distance formula of two points are

$\sqrt{(x_{2}-x_{1} ) ^{2}+ (y_{2}-y_{1} ) ^{2}}$

$r=\sqrt{{(-3)-(-1) ) ^{2}+ (2-(-2)) ^{2}}$

$r=\sqrt{5}$

Step 3:-

center (h,k) = (-2,0) and

radius $r=\sqrt{5}$

The standard form of circle equation

$(x-h)^2+(y-k)^2=r^2$

$(x-(-2))^2+(y-0)^2=\sqrt{5} ^2$

on simplification is

$x^{2} +y^{2}+4 x-1=0$

5 0

3 years ago

BRAINLIEST through: (-3,5) parallel to y=-2x-3

umka2103 [35]

Answer:

Parallel Lines have the SAME SLOPE

We first Find the Slope of the line

y = 2 x + 3

The Slope Intercept Form of the equation of a given line is:

y = m x + c

where m is the Slope of that line, and c is the Y intercept. For this line, the Slope is 2 So the Slope of the line PARALLEL to

y = 2 x + 3

will also be 2 . And we are given that it passes through the point

( − 3 , 4 )

With this, we can use the Point Slope form to find the equation of the line.

The Point-Slope form of the Equation of a Straight Line is:

( y − k ) = m ⋅ ( x − h ) m is the Slope of the Line

( h , k ) are the co-ordinates of any point on that Line.

Here, we have been given the coordinates

( h , k ) of 1 point on that line as ( − 3 , 4 )

And the Slope m is 2

Substituting the values of h , k and m in the Point-Slope form, we get

( y − 4 ) = ( 2) ⋅ ( x − ( − 3 ) )

The above will be the Equation of the Line in Point-Slope form.

If we need it in the Slope Intercept Form, we need to follow these steps:

Modifying the equation, we get:

( y − 4 ) = 2 ⋅ ( x + 3 )

y − 4 = 2 x + 6

y = 2 x + 6 + 4

We get the equation of the line as :

y = 2 x + 10

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Click on the value for p that makes this inequality true. P2 -12

Nataliya [291]

Answer:

0

Step-by-step explanation:

5 0

3 years ago

7+3z-8-3z plz answer quick i have 10 points

Naddik [55]

-1+z because 7-8 would be -1 and positive 3-3 would just be the variable after

4 0

2 years ago