Ask question

Ask question

All categories

2 years ago

13

A bag contains 2 red, 5 blue, and 3 green marbles. A marble is chosen at random. What is the probability of NOT choosing a red m

arble

1 answer:

Lapatulllka [165]2 years ago

4 0

Step-by-step explanation:

Number of red = 2
Number of blue = 5
Number of green = 3

total number of marbles = 10

<h3>probability of not choosing a red marble = 1--choosing a red marble.</h3>

<u>Because</u><u> </u><u>probability</u><u> </u><u>is</u><u> </u><u>always</u><u> </u><u>one</u><u>(</u><u>1</u><u>)</u><u>.</u>

<em>Probability</em><em> </em><em>=</em>

<em> $1 - \frac{2}{10}$ </em>

<em> $\frac{8}{10}$ </em>

<em> $\frac{4}{5}$ </em>

<em>Is</em><em> </em><em>the</em><em> </em><em>probability</em><em> </em><em>of</em><em> </em><em>not</em><em> </em><em>choosing</em><em> </em><em>a</em><em> </em><em>red</em><em> </em><em>marble</em><em>.</em>

You might be interested in

To which subsets of real numbers does the following number belong? square root of 30

LenaWriter [7]

In order to determine which subset it belongs, we must rewrite

$\sqrt(30)$

as

$\sqrt(30)=\sqrt(2\times \times 3 \times 5)$

$\Rightarrow \sqrt(30)=\sqrt(2 \times 3\times 5)$

$\Rightarrow \sqrt(30)=\sqrt(2) \times \sqrt(3) \times \sqrt(5)$

All these three numbers are irrational numbers, hence their product is also irrational

<h2> $\Rightarrow \sqrt(30)$ </h2><h2>belongs to the set of irrational numbers</h2>

6 0

3 years ago

Read 2 more answers

Roberta makes $9 an hour plus a 10.5% commission selling jewelry an hour shift in which she sells $880 worth of jewelry. How muc

timama [110]

Answer:

Roberta earns $164.4 on an 8 hr shift.

Step-by-step explanation:

In one hour Roberta makes $9

So if she works for 8 hours she will be making

=> ( 9 X 8)$

=>72$

Also she earns a commission of 10.5% on selling a jewellery worth $880

So 10.5% of 880 is

=> $\frac{10.5}{100}\times 880$

=> $0.105\times 880$

=> 92.4

Hence Roberta will be earning a total amount of

(72+ 92.4)

=>$164.4

3 0

3 years ago

9. Gold miners in Alaska have found, on average, 12 ounces of gold per 1000 tons of dirt excavated with a standard deviation of

netineya [11]

Answer:

9.18% probability the miners find more than 16 ounces of gold in the next 1000 tons of dirt excavated

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 12, \sigma = 3$

What is the probability the miners find more than 16 ounces of gold in the next 1000 tons of dirt excavated?

This is 1 subtracted by the pvalue of Z when X = 16. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{16 - 12}{3}$

$Z = 1.33$

$Z = 1.33$ has a pvalue of 0.9082

1 - 0.9082 = 0.0918

9.18% probability the miners find more than 16 ounces of gold in the next 1000 tons of dirt excavated

5 0

2 years ago

Does anyone know how to do this?

eduard

Answer:

on 60!! Hope this help's

Step-by-step explanation:

6 0

2 years ago

A debate team of 4 members for a high school will be chosen randomly from a potential group of 15 students. Ten of the 15 studen

iragen [17]

Answer:

A) 0.1538

Step-by-step explanation:

4 members are going to be chosen:

M1 - M2 - M3 - M4

We have to find the probability that for each member, one without experience is chosen. There is no replacents.

Initially, we have 15 students, of which 10 have none experience. So the probability that M1 is chosen as a student with no experience is $\frac{10}{15}$ .

Then, there are 14 students, of which 9 have no experience. So the probability that M2 is chosen as a student with no experience is $\frac{9}{14}$ .

For the third member, there are 13 students, of which 8 have no experience. So the probability that M3 is chosen as a student with no experience is $\frac{8}{13}$ .

For the last member, there are 12 students, of which 7 have no experience. So the probability that M4 is chosen as a student with no experience is $\frac{7}{12}$ .

What is the probability that none of the members chosen for the team have any competition experience?

This is

$P = \frac{10}{15}*\frac{9}{14}*\frac{8}{13}*\frac{7}{12} = 0.1538$

The correct answer is:

A) 0.1538

7 0

3 years ago