All categories

3 years ago

Use the rules of significant figures to simplify the following expression: 47.2 - 6

Mathematics

1 answer:

Lostsunrise [7]3 years ago

7 0

Answer:

41.2

Step-by-step explanation:

You might be interested in

How to do 3/4.5-3/8.0

svet-max [94.6K]

7/24 I hope this helps you

7 0

3 years ago

HELPPPPPPPPPPPPPPPPpppp

s344n2d4d5 [400]

Answer: 32π
Decimal: 100.53 (Not rounded)

Formula for a Cone: ⅓ πr^2h.

5 0

3 years ago

The product of 7 and a number is 126. Find the number

fenix001 [56]

Answer:

Step-by-step explanation:

Product of 7 and a number is 126.

Let's form the equation,

→ 7 × x = 126

The required value of x will be,

→ 7 × x = 126

→ x = 126/7

→ [ x = 18 ]

Hence, the number is 18.

6 0

2 years ago

Find a formula for the nth partial sum of the series and use it to find the series' sum if the series converges.

Arisa [49]

Answer: $S_n=5(1-\dfrac{1}{n+1})$ ; 5

Step-by-step explanation:

Given series : $[\dfrac{5}{1\cdot2}]+[\dfrac{5}{2\cdot3}]+[\dfrac{5}{3\cdot4}]+....+[\dfrac{5}{n\cdot(n+1)}]$

Sum of series = $S_n=\sum^{\infty}_{1}\ [\dfrac{5}{n\cdot(n+1)}]=5[\sum^{\infty}_{1}\dfrac{1}{n\cdot(n+1)}]$

Consider $\dfrac{1}{n\cdot(n+1)}=\dfrac{n+1-n}{n(n+1)}$

$=\dfrac{1}{n}-\dfrac{1}{n+1}$

⇒ $S_n=5\sum^{\infty}_{1}\dfrac{1}{n\cdot(n+1)}=5\sum^{\infty}_{1}[\dfrac{1}{n}-\dfrac{1}{n+1}]$

Put values of n= 1,2,3,4,5,.....n

⇒ $S_n=5(\dfrac{1}{1}-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+......-\dfrac{1}{n}+\dfrac{1}{n}-\dfrac{1}{n+1})$

All terms get cancel but First and last terms left behind.

⇒ $S_n=5(1-\dfrac{1}{n+1})$

Formula for the nth partial sum of the series :

$S_n=5(1-\dfrac{1}{n+1})$

Also, $\lim_{n \to \infty} S_n = 5(1-\dfrac{1}{n+1})$

$=5(1-\dfrac{1}{\infty})\\\\=5(1-0)=5$

4 0

3 years ago

What's a equation for $150 dollars for 50 T-Shirts

emmasim [6.3K]

150 devided by 50 = 30

7 0

3 years ago