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ankoles [38]
2 years ago
8

Can someone help me with this question please.

Mathematics
1 answer:
galina1969 [7]2 years ago
5 0

Answer:

6, 8, and 10.

Step-by-step explanation:

You could work this out with the pythagorean theorem, by proving that 6^2, 36, plus 8^2, 64, equals 100. The fastest way, however, is to use pythagorean triples. These are predetermined sets of numbers that work as side lengths for right triangles. The first two are 3, 4, and 5, which form a right triangle, and 6, 8, and 10, shown here.

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4 0
3 years ago
Question in the middle please
oksian1 [2.3K]
So it wants you to write two equations, one for the number of fruit and another for the money spent. gather your important information first:

20 fruits for $11.50
apples cost $0.50
bananas cost $0.75

let's do the cost equation first. it's $0.50 per apple, so 0.50a, and $0.75 per banana, so 0.75b. the total cost is $11.50. put all of this information together:

0.50a + 0.75b = 11.50  ... so, the cost of apples bought plus the cost of bananas bought equals 11.50

note what your variables stand for. a represents the number of apples, b represents the number of bananas. to write an equation for how many fruits bought, you simply have to add these two and set them equal to 20 (the total number of fruits bought).

a + b = 20
and your other equation
0.50a + 0.75b = 11.50

these are your two equations. to solve the system of equations, you first want to get one variable alone; the first equation will be easier.

a + b = 20
a = 20 - b

now take this equation and plug it into the second equation.
0.50(20 - b) + 0.75b = 11.50 ... you'll notice that you only have one variable left: b. solve for it. the first step is to distribute 0.50 to the parentheses
10 - 0.50b + 0.75b = 11.50 ... combine like terms
10 + 0.25b = 11.50 ... subtract 10
0.25b = 1.5 ... divide by 0.25
b = 6

6 bananas were purchased. plug this back into an equation to find out how many apples were purchased.

a + 6 = 20 ... subtract 6
a = 14

14 apples and 6 bananas were bought.
3 0
3 years ago
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