To find area you multiply the height and width so which ever are the height and width out of those numbers you multiply them together
Well, we can denote L and W for the length and width respectively. Lets say the A is the area, we have: 1. A=(L × W) as well as 2. 2(L+W)=400. We rearrange the second equation to get 3. W=200-L. From this, we can see that 0<L<200. Substitute the third equation into the first to get A=(200L-L²). put this formula into the scientific calculator and you will find a parabola with a maximum. That would be the maximum area of the enclosed area. Alternatively, we can say that L is between 0 and 200 when the area equals 0. (The graph you find will be area against length). As the maximum is generally found halfway, we substitute 100 into the equation and we end up with 10000.
Hope this helps.
In this equation w = -1.1
In order to find this, get all w values to the right side and all numbers to the left side.
-2.27 + 9.1w + 1.3w = -3.4w - 17.45 ----> combine like terms
-2.27 + 10.4w = -3.4w - 17.45 ----> add 3.4w to both sides
-2.27 + 13.8w = -17.45 ----> add 2.27 to both sides
13.8w = -15.18 -----> divide both sides by 13.8
w = -1.1
We have that
<span>If (5x-4+13x=5) --------------> then x=1/2
Step 1
</span>let's substitute the value of x = (1/2) in the expression [5x-4+13x] and verify its result
5*(1/2)-4+13*(1/2)
(5/2)-4+(13/2)
(5-4*2+13)/2----------> (5-8+13)/2=10/2=5
then
5=5-----------> <span>the value of x = (1/2) satisfies equality</span>