Answer:
the answer is d!! I hope it helped please lmk if not
The complete question in the attached figures N 1 and N 2
we have that
<span>the following system of inequalities:
y ≥ −3x + 1
y ≤ (1/2)x + 3
using a graph tool
see the attached figure N 3
the answer is the option
</span><span>
B)Graph of two lines that intersect at one point. Both lines are solid. One line passes through points negative 2, 2 and 0, 3 and is shaded below the line. The other line passes through points 0, 1 and 1, negative 2 and is shaded above the line.</span>
Answer:
(1,0), (0,0),(-2<0)<(-1, -2)
Step-by-step explanation:
Answer:
Their are no possible factors for this expression.
Step-by-step explanation:
So I'm assuming that you're taking Calculus.
The first thing you want to do is take the integral of f(x)...
Use the power rule to get:
4X^2-13X+3.
Now solve for X when f(x)=0. This is because when the slope is 0, it is either a minimum or a maximum(I'm assuming you know this)
Now you get X=0.25 and X=3. Since we are working in the interval of (1,4), we can ignore 0.25
Thus our potential X values for max and min are X=1,X=4,X=3(You don't want to forget the ends of the bounds!)
Plugging these value in for f(x), we get
f(1)=2.833
f(3)=-8.5
f(4)=1.667
Thus X=1 is the max and X=3 is the min.
So max:(1,2.833)
min:(3,-8.5)
Hope this helps!