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3 years ago

Math test. help plz!

Mathematics

2 answers:

VikaD [51]3 years ago

5 0

Answer:

7 squared is 49 So your answer is 49

Step-by-step explanation:

Good luck.

almond37 [142]3 years ago

3 0

Answer:

49 plug x=7 into the equation

Step-by-step explanation:

you are welcome

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Y’all pls help me kanajkabawiajjajqjqkqknabajokqnqq

kaheart [24]

Answer:

help with what? what is your q u e s t i o n

Step-by-step explanation:

8 0

2 years ago

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HURRY! What are all the possible rational solutions for x^4-3x^2+2x5=0

xxTIMURxx [149]

Answer: x = 1

x =(-3-√-15)/4=(-3-i√ 15 )/4= -0.7500-0.9682i

x =(-3+√-15)/4=(-3+i√ 15 )/4= -0.7500+0.9682i

x2 = 0

Step-by-step explanation:

4 0

2 years ago

Which correctly gives the expression using addition? –17.9 – 4.2

Shkiper50 [21]

c. –17.9+(–4.2)

The General rule for adding and subtracting numbers 
1. Two integers with the same signs
Once 2 integers has the same sign, then just add the numbers.
For example
1. 1+1 = 2 
2. 2 + 5 = 7 

2. Two integers with different signs
When 2 integers has different sign, then find the difference
For example
1. 1-1 =0
2. 2 – 5 = -3 

3. Two integers that vary in sign
When 2 integers vary in sign, then it will depend who which number carries the largest value
For example 
1. -3 + 2 = -1
2. 2 – 1 = 1

5 0

3 years ago

Match each interval with its corresponding average rate of change for q(x) = (x + 3)2. 1. -6 ≤ x ≤ -4 1 2. -3 ≤ x ≤ 0 -4 3. -6 ≤

MrMuchimi

The average rate of change of a function f(x) in an interval, a < x < b is given by
$\frac{f(b) - f(a)}{b - a}$

Given q(x) = (x + 3)^2

1.) The average rate of change of q(x) in the interval -6 ≤ x ≤ -4 is given by $\frac{q(-4)-q(-6)}{-4-(-6)} = \frac{(-4+3)^2-(-6+3)^2}{-4+6} = \frac{1-9}{2} = \frac{-8}{2} =-4$

2.) The average rate of change of q(x) in the interval -3 ≤ x ≤ 0 is given by $\frac{q(0)-q(-3)}{0-(-3)} = \frac{(0+3)^2-(-3+3)^2}{0+3} = \frac{9-0}{3} = \frac{9}{3} =3$

3.) The average rate of change of q(x) in the interval -6 ≤ x ≤ -3 is given by $\frac{q(-3)-q(-6)}{-3-(-6)} = \frac{(-3+3)^2-(-6+3)^2}{-3+6} = \frac{0-9}{3} = \frac{-9}{3} =-3$

4.) The average rate of change of q(x) in the interval -3 ≤ x ≤ -2 is given by $\frac{q(-2)-q(-3)}{-2-(-3)} = \frac{(-2+3)^2-(-3+3)^2}{-2+3} = \frac{1-0}{1} = \frac{1}{1} =1$

5.) The average rate of change of q(x) in the interval -4 ≤ x ≤ -3 is given by $\frac{q(-3)-q(-4)}{-3-(-4)} = \frac{(-3+3)^2-(-4+3)^2}{-3+4} = \frac{0-1}{1} = \frac{-1}{1} =-1$

6.) The average rate of change of q(x) in the interval -6 ≤ x ≤ 0 is given by $\frac{q(0)-q(-6)}{0-(-6)} = \frac{(0+3)^2-(-6+3)^2}{0+6} = \frac{9-9}{6} = \frac{0}{6} =0$

3 0

3 years ago

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If you know the equation of a proportional relationship how can you draw the graph of the equation

zalisa [80]

The equation of proportional relationship is of the form:
$y(x)=mx$

where m is the slope.

Drawing it is fairly easy, you start from the origin (0, 0) and you draw a diagonal staight line. The inclination of the line depends on the value of m. See picture attached.

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3 years ago