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gulaghasi [49]
3 years ago
15

What do liquid methane and liquid water have in common

Chemistry
2 answers:
Andru [333]3 years ago
7 0

Answer:

Methane on the other hand, is made of one carbon atom and 4 hydrogen atoms. Like water, the bonds are covalent. ... Because water displays hydrogen bonding with other molecules, a large amount of heat energy is required to break this, and water's boiling point is around 100 degrees celsius.

Explanation:

I hope this helps answer your question

:D

Mekhanik [1.2K]3 years ago
3 0

Answer:

methane on the other hand is made of one carbon atom and 4 hydrogen atoms. like water, the bonds are covalent.

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En un recipiente cerrado y rígido se introdujo una mezcla gaseosa a cierta temperatura y las presiones parciales de cada gas son
valkas [14]

Answer:

Qp > Kp, por lo tanto, la presión parcial de BrF₃(g) aumenta hasta alcanzar el equilibrio.

Explanation:

Paso 1: Escribir la ecuación balanceada

BrF₃ (g) ⇌ BrF(g) + F₂(g)      Kp(T) = 64,0

Paso 2: Calcular el cociente de reacción (Qp)

Qp = pBrF × pF₂ / pBrF₃

Qp = 1,50 × 2,00 / 0,0150 = 200

Paso 3: Sacar una conclusión

Dado que Qp > Kp, la reacción se desplazará hacia la izquierda para alcanzar el equilibrio, es decir, la presión parcial de BrF₃(g) aumenta hasta alcanzar el equilibrio.

7 0
3 years ago
Can somebody plz help answer this science questions (only 1-2 sentences is good thx !
Mrac [35]
I believe it’s because they are trying to find other things that won’t pollute the environment as much, and they are also doing this because we are trying to reduce green house gas. Sorry if i’m wrong :(
8 0
3 years ago
*Riddle!* *Riddle!!* *Riddle!!!*
otez555 [7]

Answer:

https://www.getriddles.com/science-riddles/

Explanation:

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5 0
3 years ago
A generic weak acid with formula HA has a Ka = 2.76 x 10-8. Calculate the Kb for the conjugate base of the acid.
Reika [66]

Answer:

3.62x10⁻⁷ = Kb

Explanation:

The acid equilibrium of a weak acid, HX, is:

HX + H₂O ⇄ X⁻ + H₃O⁺

Where Ka = [X⁻] [H₃O⁺] / [HX]

And basic equilibrium of the conjugate base, is:

X⁻ + H₂O ⇄ OH⁻ + HX

Where Kb = [OH⁻] [HX] / [X⁻]

To convert Ka to Kb we must use water equilibrium:

2H₂O ⇄ H₃O⁺ + OH⁻

Where Kw = 1x10⁻¹⁴ = [OH⁻] [H₃O⁺]

Thus, we can obtain:

Kw = Ka*Kb

Solving for Kb:

Kw / Ka = Kb

1x10⁻¹⁴ /  2.76x10⁻⁸ =

3.62x10⁻⁷ = Kb

4 0
3 years ago
BALANCING CHEMICAL EQUATIONS WORKSHEET
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Answer:

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Explanation:

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