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MAVERICK [17]
3 years ago
13

A world without friction would it be? Bill Nye Video

Chemistry
1 answer:
cupoosta [38]3 years ago
8 0

Answer:

it opposes motion. the object would continue to slide forever if not stopped by another object.

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Fe + Ph(NO3)2 ==> Pb + Fe(NO3)2
Ahat [919]
There seems to be a mistake. If u mistyped the 'h', then the reaction is single replacement.
5 0
3 years ago
What is a chemical treatment process used to remove dissolved ionic species from contaminated aqueous streams?
NeTakaya

Answer:

Ion exchange.

Explanation:

One of the ways in which water can be treated is through the process known as ION EXCHANGE. Using this for treating water has to do basically with the transfer or say the exchange of ions.

Ion exchanges is done by exchanging ions which are considered as 'unfit' or contaminants by the ones that are "fit".

Ions from what is known as zeolite or resin is been exchanged with the ions in the water. Cations are exchanged with cations and anions are exchanged with anions.

NB: this method is a good method or removing contaminants that are ions but not contaminants that are not ions.

6 0
3 years ago
When are igneous rocks formed?
balandron [24]

Answer:

C. When melted rock solidifies.

3 0
3 years ago
He rate constant of a reaction is 4.55 × 10−5 l/mol·s at 195°c and 8.75 × 10−3 l/mol·s at 258°c. what is the activation energy o
Xelga [282]

Answer : The activation energy of the reaction is, 17.285\times 10^4kJ/mole

Solution :  

The relation between the rate constant the activation energy is,  

\log \frac{K_2}{K_1}=\frac{Ea}{2.303\times R}\times [\frac{1}{T_1}-\frac{1}{T_2}]

where,

K_1 = initial rate constant = 4.55\times 10^{-5}L/mole\text{ s}

K_2 = final rate constant = 8.75\times 10^{-3}L/mole\text{ s}

T_1 = initial temperature = 195^oC=273+195=468K

T_2 = final temperature = 258^oC=273+258=531K

R = gas constant = 8.314 kJ/moleK

Ea = activation energy

Now put all the given values in the above formula, we get the activation energy.

\log \frac{8.75\times 10^{-3}L/mole\text{ s}}{4.55\times 10^{-5}L/mole\text{ s}}=\frac{Ea}{2.303\times (8.314kJ/moleK)}\times [\frac{1}{468K}-\frac{1}{531K}]

Ea=17.285\times 10^4kJ/mole

Therefore, the activation energy of the reaction is, 17.285\times 10^4kJ/mole

8 0
3 years ago
Read 2 more answers
HELP PLEASE !!!! DUE NOW!!
ratelena [41]

Answer:

The ratio of the products to reactants remains caonstant over time

Explanation:

6 0
3 years ago
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