There would be a forty percent change should would serve as an ace next match.
4*4=16
10*4=40
Given that the projectiles have been given by the functions:
H(t)=-16t^2+96t+80 and G(t)=31+32.2t
Part A:
The tables for the functions will be as follows:
t 2 3 4 5
H(t) 208 224 208 160
t 2 3 4 5
G(t) 95.4 127.6 159.8 198
The solution is found between points:
4th second and 5th second
i] It's between this point that the graph H(t) is has reached the maximum point and it's now turning. So the points of H(t) are nearing points for G(t).
Part B]
The solution in part A implicates the times at which the projectiles were at the same height and the time at which they were at the same heights.
Answer:
...
Step-by-step explanation:
Answer:
Step-by-step explanation:
Easiest way would be to substitute points into the given equations and plot your answers.
E.g. if you substitute points into your first equation you get:
If x = 0, y = -4(0) +2 = 2
If x = 1, y = -4(1) +2 = -2
If x = -1, y = -4(-1) +2 = 6
Etc.
Second equation:
If x = 0, y= -(0) -1 = -1
If x = 1, y = -1 -1 = -2
If x = -1, y = -(-1) -1 = 0
Pretty much just plug in values for x into the equations to find y.
Once you have your points, draw a line :)
Where the two lines intercept would be the solution.
Yes ABD=CBD since they both are just half of the triangle
