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2 years ago

What is the geometric mean og 6 and 13

Mathematics

1 answer:

lara31 [8.8K]2 years ago

6 0

Answer:

The answer is

Step-by-step explanation:

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Complete the following: (2x +3y)^2 = (2x)^2+2(2x)(3y) +(____)^2

FrozenT [24]

Answer:

Complete function will be $(2x+3y)^2=(2x)^2+(3y)^2+2\times (2x)\times (3y)$

Step-by-step explanation:

We have given equation $(2x+3y)^2=(2x)^2+2\times (2x)\times (3y)+..........^2$

We have to find the function in place of blank space and complete the function

We know the algebraic equation $(a+b)^2=a^2+b^2+2ab$

So $(2x+3y)^2=(2x)^2+(3y)^2+2\times (2x)\times (3y)$

So in place of blank pace there will be $(3y)^2$

And complete function will be $(2x+3y)^2=(2x)^2+(3y)^2+2\times (2x)\times (3y)$

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3 years ago

Last one i swear, i'll give brainliest :)

svlad2 [7]

Answer:

95% since 19÷20 is 0.95 which multiplied by hundred is 95

3 0

3 years ago

What percent of 33.75 is 27?

My name is Ann [436]

Answer:

27 is 80% of 33.75

Step-by-step explanation:

3 0

3 years ago

write an expression for the calculation the difference of 35 and 7 divided by the difference of 9 and 2

Rudik [331]

Answer:

35-7/ 9-2

28/7

Step-by-step explanation:

6 0

3 years ago

Write the equation of the line in slope intercept form that passes through the point (-3, 5) and is parallel to y= - 2/3x

Solnce55 [7]

Answer:

The equation of the line in slope intercept form that passes through the point (-3, 5) and is parallel to y= - 2/3x is $\mathbf{y=-\frac{2}{3}x+3 }$

Step-by-step explanation:

We need to Write the equation of the line in slope intercept form that passes through the point (-3, 5) and is parallel to y= - 2/3x

The equation in slope-intercept form is: $y=mx+b$ where m is slope and b is y-intercept.

Finding Slope:

The both equations given are parallel. So, they have same slope.

Slope of given equation y= - 2/3x is m = -2/3

This equation is in slope-intercept form, comparing with general equation $y=mx+b$ where m is slope , we get the value of m= -2/3

So, slope of required line is: m = -2/3

Finding y-intercept

Using slope m = -2/3 and point (-3,5) we can find y-intercept

$y=mx+b\\5=-\frac{2}{3}(-3)+b\\5=2+b\\ b=5-2\\b=3$

So, we get b = 3

Now, the equation of required line:

having slope m = -2/3 and y-intercept b =3

$y=mx+b\\y=-\frac{2}{3}x+3$

The equation of the line in slope intercept form that passes through the point (-3, 5) and is parallel to y= - 2/3x is $\mathbf{y=-\frac{2}{3}x+3 }$

5 0

3 years ago

Read 2 more answers