Answer:
4 times as tall.
Step-by-step explanation:
Volume of the box with the smaller base = 2*2* h1 = 4h1 where h1 is its height.
Similarly the volume of the larger base box = 4*4 * h2 = 16h2 with height h2.
So the ratio of their volumes is 16h2 / 4h1 = 4h2 / h1.
Now the volumes are equal so 4h2 = h1.
Therefore h2 = h1/4 so h1 = 4h2.
The box with the smaller base is 4 times as tall as the other box.
To solve this, I'm assuming that the equations both represent angles:
There is a theorem that states that an exterior angle of a triangle is equivalent to the sum of two remote triangles. Knowing this:
11x + 7 = 7x + 14 + 25
11x + 7 = 7x + 39
4x = 32
x = 8
"Increasing" and "decreasing" are references to what the y-values do when the x-values increase.
Attached is a copy of all four tables, marked with whether the y-values increased or decreased on each step (and it also shows how much that increase or decrease was.
The only table that does this is the top right table in the attachment, which is your second table.
Answer:
x=0
y=-14
Step-by-step explanation:
If the equation is y=2x-14,
If x=0,
enter x into the equation
y=2(0)-14
y=0-14
y=-14
Answer:
1 m³
Step-by-step explanation:
first find volume of smaller cubes
V = lwh
S = 1/3*1/3*1/3
S = 1/27
find volume of large cube. there are 27 smaller cubes.
V = 27S
V = 27(1/27)
V = 1
S: volume of small cube
V: volume of large cube
