Help me pleaseeeeeeeeeee
2 answers:
7x + 6y = -42
For this case what you should do is see the intersections with each of the axes and then join the ordered pairs.
We have then:
For the x axis:
y = 0
Substituting in the equation:
7x + 6 (0) = - 42
7x + 0 = -42
x = -6
For the y axis:
x = 0
Substituting in the equation:
7 (0) + 6y = -42
0 + 6y = -42
y = -42 / 6
y = -7
We graph the ordered pairs:
(x1, y1) = (- 6, 0)
(x2, y2) = (0, -7)
Answer:
See attached graph.
For this case what you should do is see the intersections with each of the axes and then join the ordered pairs.
We have then:
For the x axis:
y = 0
Substituting in the equation:
7x + 6 (0) = - 42
7x + 0 = -42
x = -6
For the y axis:
x = 0
Substituting in the equation:
7 (0) + 6y = -42
0 + 6y = -42
y = -42 / 6
y = -7
We graph the ordered pairs:
(x1, y1) = (- 6, 0)
(x2, y2) = (0, -7)
Answer:
See attached graph.
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Quadratic f(x) = (x -h)² +k has vertex (h, k) and axis of symmetry x=h. When k is negative, the number of real solutions is 2, because both branches of the function cross the x-axis.
In your equation, h = -3 and k = -8.
Axis of symmetry: x = -3
Vertex: (-3, -8)
Number of real solutions: 2
In your equation, h = -3 and k = -8.
Axis of symmetry: x = -3
Vertex: (-3, -8)
Number of real solutions: 2