Answer:
I believe A is the answer
Answer:
Two times at (-1,0) and (2.5,0)
Step-by-step explanation:
When the graph intersects or touches x-axis, y is equal to 0
so y = -2x^2 + 3x + 5
=> 0 = -2x^2 + 3x + 5
The formula to solve a quadratic equation of the form ax^2 + bx + c = 0 is equal to x = [-b +/-√(b^2 - 4ac)]/2a
so a = -2
b = 3
c = 5
substitute in the formula
x = [-3 +/- √(3^2 - 4x-2x5)]/2(-2)
x = [-3 +/- √(9 + 40)]/(-4)
x = [-3 +/- 7]/(-4)
x1 = (-3 + 7)/(-4) = 4/-4 = -1
x2 = (-3 - 7)/(-4) = -10/-4 = 5/2 = 2.5
so the graph has two x-intercepts (-1,0) and (2.5,0), therefore it intersects x-axis two times
Find the inverse, interchange the variables to solve for y
f-1 (x)=-
![\frac{8- \sqrt[]{_2(-8+x)} }{2} ,](https://tex.z-dn.net/?f=%20%5Cfrac%7B8-%20%5Csqrt%5B%5D%7B_2%28-8%2Bx%29%7D%20%7D%7B2%7D%20%2C)
Answer:1/5
Step-by-step explanation:
most members prefer a beach vacation
