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2 years ago

What is the equation of a line with a slope of 4 and a y-intercept of 2?

Mathematics

2 answers:

Trava [24]2 years ago

6 0

Answer:

y=4x+2 or f(x)=4x+2

Step-by-step explanation:

This is because the equation format for a line is y=mx+b, the slope is m and the y-intercept is b. So all you have to do is fill it out to get y=4x+2. Or the other way I listed the equation is right too. Hope this helps!

Kamila [148]2 years ago

4 0

The regular formula for slope is y=mx+b
Y=mx+b
m-slope
b- y-intercept

So you’re answer would be
Y=4x+2

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What’s the inverse equation? And how you solved it step by step please!

Korvikt [17]

Answer:

The inverse is (x^2-5)/2

Step-by-step explanation:

y =sqrt(2x+5)

Exchange x and y

x = sqrt(2y+5)

Solve for y

Square each side

x^2 = (sqrt(2y+5))^2

x^2 = 2y+5

Subtract 5 from each side

x^2 -5 = 2y-5+5

x^2 -5 = 2y

Divide each side by 2

(x^2-5)/2 = 2y/2

(x^2-5)/2 = y

The inverse is (x^2-5)/2

7 0

2 years ago

If ΔOPQ is dilated from point Q by a scale factor of 3, which of the following equations is true about segment R prime S prime?

Sergio [31]

Answer:

$\overline {R'S'} = 3 {\overline {RS} }$

Step-by-step explanation:

The scale factor of dilation of triangle ΔOPQ, S.F. = 3

The center of dilation = Point <em>Q</em>

Therefore;

The length of the segment, ${\overline {S'Q'} }$ = 3 × The length of the segment, ${\overline {SQ} }$

Similarly;

The length of the segment, ${\overline {R'Q'} }$ = 3 × The length of the segment, ${\overline {RQ} }$

By Pythagoras theorem, we have;

${\overline {R'Q'} }^2 = {\overline {R'S'} }^2 + {\overline {S'Q'} }^2$

Therefore;

${\overline {R'S'} }^2 = {\overline {R'Q'} }^2 - {\overline {S'Q'} }^2 = \left ({3 \times \overline {RQ} } \right) ^2 - \left (3 \times {\overline {SQ} } \right) ^2 = 9 \times \left (\overline {RQ} } ^2 - {\overline {SQ} } ^2 \right) = 9 \times {\overline {RS} }^2$