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Amiraneli [1.4K]
2 years ago
12

What is the equation of a line with a slope of 4 and a y-intercept of 2?

Mathematics
2 answers:
Trava [24]2 years ago
6 0

Answer:

y=4x+2 or f(x)=4x+2

Step-by-step explanation:

This is because the equation format for a line is y=mx+b, the slope is m and the y-intercept is b. So all you have to do is fill it out to get y=4x+2. Or the other way I listed the equation is right too. Hope this helps!

Kamila [148]2 years ago
4 0
The regular formula for slope is y=mx+b
Y=mx+b
m-slope
b- y-intercept

So you’re answer would be
Y=4x+2
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Alex

Answer:

The correct answer would be B

Step-by-step explanation:

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3 years ago
Write the expression 18 - 27-9 in the form of a +bi.
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A byte is used to measure a computer's memory. There are 2^30 bytes in a gigabyte. A computer has an 8 gigabyte memory. Which ex
aksik [14]

Answer:

8x2^30

Step-by-step explanation:

5 0
3 years ago
What happens if you double 15?
Andrej [43]

Answer:

It becomes 30

Step-by-step explanation:

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8 0
3 years ago
Read 2 more answers
What is the solution of x=2+ square root x-2?
alex41 [277]

So I'm going to assume that this question is asking for <u>non extraneous solutions</u>, or solutions that are found in the equation <em>and</em> are valid solutions when plugged back into the equation. So firstly, subtract 2 on both sides of the equation:

x-2=\sqrt{x-2}

Next, square both sides:

(x-2)^2=x-2\\(x-2)(x-2)=x-2\\x^2-4x+4=x-2

Next, subtract x and add 2 to both sides of the equation:

x^2-5x+6=0

Now we are going to be factoring by grouping to find the solution(s). Firstly, what two terms have a product of 6x^2 and a sum of -5x? That would be -3x and -2x. Replace -5x with -2x - 3x:

x^2-2x-3x+6=0

Next, factor x^2 - 2x and -3x + 6 separately. Make sure that they have the same quantity on the inside of the parentheses:

x(x-2)-3(x-2)=0

Now you can rewrite the equation as (x-3)(x-2)=0

Now, apply the Zero Product Property and solve for x as such:

x-3=0\\x=3\\\\x-2=0\\x=2

Now, it may appear that the answer is C, however we need to plug the numbers back into the original equation to see if they are true as such:

2=2+\sqrt{2-2}\\2=2+\sqrt{0}\\2=2+0\\2=2\ \textsf{true}\\\\3=2+\sqrt{3-2}\\3=2+\sqrt{1}\\3=2+1\\3=3\ \textsf{true}

Since both solutions hold true when x = 2 and x = 3, <u>your answer is C. x = 2 or x = 3.</u>

8 0
3 years ago
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