to find the area of a rectangle is LxW=A
plug in the given numbers you have
L = 7
W = x-8
A = 42
7 * x-8 = 42
7x-56= 42
solve for X
If you think about it, you have your answer in your question.
Convert 2/4 to 1/2 which in decimal form, is .5.
You’re final answer is -2.3,-2 2/4,-2.6.
I hope this helps!
Rectangle on the left = 3 × 4 = 12
Rectangle in the middle = 3 × 2 = 6
Rectangle on the right = 4 × 3 = 12
Add:
12 + 6 + 12 = 30
Answer = 30
Hope this helped☺☺
Answer: Any real number x as long as
and 
In other words, anything but 0 or -2/3 is valid.
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Explanation:
Set the denominator equal to zero and solve for x
2(3x^2 + 2x) = 0
3x^2 + 2x = 0
x(3x + 2) = 0
x = 0 or 3x+2 = 0 .... zero product property
x = 0 or 3x = -2
x = 0 or x = -2/3
If either x = 0 or x = -2/3, then the denominator 2(3x^2 + 2x) will be zero. But recall that we cannot have zero in the denominator. Dividing by zero is not allowed. The expression is undefined when we divide by zero.
Therefore, we must exclude x = 0 and x = -2/3 from the domain. Any other real number is valid as an x input.
Answer: 4x^2−4x+1
Step-by-step explanation:
(2x-1)^2
Square of Difference: (a−b)^2=a^2−2ab+b^2.
(2x)^2−2*2x+1
Multiplication Distributive Property: (xy)^a=
2^2x^2−2*2x+1
4x^2−2*2x+1
4x^2−4x+1
Hope this helps, now you know the answer and how to do it. HAVE A BLESSED AND WONDERFUL DAY! As well as a great Valentines Day! :-)
- Cutiepatutie ☺❀❤