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SpyIntel [72]
3 years ago
10

Please help thank you ahead of time

Mathematics
1 answer:
vlabodo [156]3 years ago
6 0
Okay so basically, i’m pretty sure you have to make them catch up with each other, if i’m correct), so if it’s 30 to each student plus 2500 then 2 students is 60 bucks, 3 students is 90 and so on so forth......then if 1 student - 60 then 2 is 120 and vice versa ya know. So keep adding on the amount due for each student plus the extra amount which doesn’t change and make them catch up with each other. Keep on adding student after student and adding the fee until they match up. Sorry it’s not the exact answer but i hope this explains it... if i’m right
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Plz give correct answer! (might give brainliest) :)<br><br><br> thnx, have a nice day!
neonofarm [45]

Answer:

56

Step-by-step explanation:

(14-7)×(40-32)

(7)×(8)

56

5 0
3 years ago
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Given h(x) = 4x + 3, find h(-1)<br>​
dsp73

Answer:

-1

Step-by-step explanation:

4x-1=-4

-4+3=-1

7 0
3 years ago
Help on this question plss!
GuDViN [60]
Adding 4 to both side is wrong he has to be subtract 4 to both side
7 0
3 years ago
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Adar, Chi, and Melissa each left the party by themselves. In how many different orders can they leave?
Leona [35]
The answer is A they can only be in different orders
4 0
3 years ago
A researcher is planning to compare the effects of two different types of lights on the growth of bean plants. She expects that
kicyunya [14]

Answer:

The sample size is  n  = 36

Step-by-step explanation:

From the question we are told that

   The sample standard deviation is  s =  1.5

  The mean difference of the two groups is  \=x _ 1 - \=x_2 =  1

   The standard error is  SE =  \frac{ \= x_1 - \= x_2}{4}

=>                                      SE =  \frac{1}{4}

Let assume that the confidence level is 95% hence the level of significance is  

   \alpha = (100-95)\%

=> \alpha = 0.05

So the critical value of  \frac{\alpha }{2} obtained from the normal distribution table is

     Z_{\frac{\alpha }{2} } = 1.96

Generally the margin of error is mathematically evaluated as

     E =  Z_{\frac{\alpha }{2} } * SE    

   E =  1.96 * \frac{1}{4}

    E = 0.49

Generally the sample size is mathematically represented as

  n =[ \frac{Z_{\frac{\alpha }{2}  * s^2}}{E}]^2

=> n  = [\frac{1.96 * 1.5}{0.49} ]^2

=> n  = 36

6 0
4 years ago
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