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ICE Princess25 [194]
3 years ago
7

Bodhi has a collection of 175 dimes and nickels. The collection is worth $13.30. Which equation can be used to find n, the numbe

r of nickels in the collection? 0.1n + 0.05(n – 175) = 13.30 0.1n + 0.05(175 – n) = 13.30 0.1(n – 175) + 0.05 = 13.30 0.1(175 – n) + 0.05n = 13.30
Mathematics
2 answers:
ehidna [41]3 years ago
7 0
<h3>The fifth one<em> would be the answer </em></h3>
Andreyy893 years ago
3 0

Answer: Option D

Step-by-step explanation:

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Evaluate (-5z)^3 . Write your answer using only positive exponents. Evaluate any numerical powers.
Ludmilka [50]

Answer:

-125z³

Step-by-step explanation:

-5 times - 5 = 25 canceling negative

125 times -5 = -125

zXzXz = z to power of 3 =z³

7 0
3 years ago
Which expression is equivalent to 4x+3x+4-2x
kvv77 [185]

Answer:

5x+ 4

Step-by-step explanation:

First, put all of the x variables together. So 3x+4x=7x

7x + 4 -2x  Since the 2x is negative you can subtract it from 7x and get 5x.

you can not add the four to the 5x because it does not have a matching variable.

So, you have: 5x+ 4

6 0
3 years ago
Which expression is equivalent to 6f+f?
Elena L [17]

Answer:

A

Step-by-step explanation:

This is because 6f+f is just 7f.

f f f f f f+f = fffffff

Soooo, ONLY A gives us 7f when added together again.

f+5f+f=7f.

f+ f f f f f +f = fffffff

3 0
2 years ago
Read 2 more answers
What set of reflections would carry triangle ABC onto itself?
Lelechka [254]

Answer:

it's x- axis,y- axis,x-axis

Step-by-step explanation:

hope this will help you

4 0
3 years ago
(1/1+sintheta)=sec^2theta-secthetatantheta pls help me verify this
Xelga [282]

Answer:

See Below.

Step-by-step explanation:

We want to verify the equation:

\displaystyle \frac{1}{1+\sin\theta} = \sec^2\theta - \sec\theta \tan\theta

To start, we can multiply the fraction by (1 - sin(θ)). This yields:

\displaystyle \frac{1}{1+\sin\theta}\left(\frac{1-\sin\theta}{1-\sin\theta}\right) = \sec^2\theta - \sec\theta \tan\theta

Simplify. The denominator uses the difference of two squares pattern:

\displaystyle \frac{1-\sin\theta}{\underbrace{1-\sin^2\theta}_{(a+b)(a-b)=a^2-b^2}} = \sec^2\theta - \sec\theta \tan\theta

Recall that sin²(θ) + cos²(θ) = 1. Hence, cos²(θ) = 1 - sin²(θ). Substitute:

\displaystyle \displaystyle \frac{1-\sin\theta}{\cos^2\theta} = \sec^2\theta - \sec\theta \tan\theta

Split into two separate fractions:

\displaystyle \frac{1}{\cos^2\theta} -\frac{\sin\theta}{\cos^2\theta} = \sec^2\theta - \sec\theta\tan\theta

Rewrite the two fractions:

\displaystyle \left(\frac{1}{\cos\theta}\right)^2-\frac{\sin\theta}{\cos\theta}\cdot \frac{1}{\cos\theta}=\sec^2\theta - \sec\theta \tan\theta

By definition, 1 / cos(θ) = sec(θ) and sin(θ)/cos(θ) = tan(θ). Hence:

\displaystyle \sec^2\theta - \sec\theta\tan\theta \stackrel{\checkmark}{=}  \sec^2\theta - \sec\theta\tan\theta

Hence verified.

8 0
2 years ago
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